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boyakko [2]
3 years ago
12

Giving brainliest! Please give me the working out for the answer

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:

∠BCD is a right angle ⇒ Proved down

Step-by-step explanation:

<em>Let us revise some fact in the circle</em>

  • If the vertices of a quadrilateral lie on a circumference of a circle, then this quadrilateral is called a cyclic quadrilateral
  • In a cyclic quadrilateral, every two opposite angles are supplementary (the sum of their measures is 180°)

<em>Let us use these facts to solve the question</em>

∵ ABCD is a quadrilateral

∵ Its vertices lie of the circumference of the circle

∴ ABCD is a cyclic quadrilateral

<em>By using the facts above</em>

∴ ∠ABC and ∠ADC are supplementary

∴ m∠ABC + m∠ADC = 180° → (1)

∵ m∠ABD = m∠CBD → given

∵ m∠ABC = m∠ABD + m∠CBD

∴ m∠ABC = 2m∠CBD → (2)

∵ m∠ADB = m∠CDB → given

∵ m∠ADC = m∠ADB + m∠CDB

∴ m∠ADC = 2m∠CDB → (3)

→ Substitute (2) and (3) in (1)

∴ 2m∠CBD + 2m∠CDB = 180

→ Divide both sides by 2

∴ m∠CBD + m∠CDB = 90

In ΔBCD

∵ m∠BCD + m∠CBD + m∠CDB = 180 → Sum of angles of a triangle

∵ m∠CBD + m∠CDB = 90

∴ m∠BCD + 90 = 180

→ Subtract 90 from both sides

∴ m∠BCD + 90 - 90 = 180 - 90

∴ m∠BCD = 90°

∴ ∠BCD is a right angle ⇒ proved

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