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3 years ago

Any sensation one receives activates ____________ which take the message to the brain for processing. select one:

Biology

2 answers:

Semmy [17]3 years ago

5 0

Any sensation one receives activates <u>sensory neurons </u>which take the message to the brain for processing

Answer: Option D

<u>Explanation:</u>

The sensory neurons are the ones that are active for the five senses. They are present throughout the body. It activates immediately when a sensation like touch is felt. This sends information to the nervous system.

There are two sensory inputs;

A physical input which can be felt by touch like fire, chillness.
A chemical input like taste or smell. Sensory neurons are the transmitters that carry signal from the body skin to the nervous system.It sends these impulses to the central nervous system.

Anestetic [448]3 years ago

4 0

Answer:

Explanation:

Hmm

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In gorillas, the ability to roll the tongue is under the control of 1 gene. The R allele, which confers tongue-rolling ability,

aalyn [17]

Answer:

0.4550

Explanation:

In this example, R allele is dominant, so individuals RR and Rr can roll their tongues. If in a population of 1000 gorillas, there are 575 gorillas who can roll their tongues, they will be RR and Rr.

In this case, there is Hardy Weinberg Equilibrium, so the following will be true:

$p^{2}+2pq+q^{2}=1$

Where:

$p^{2}=$ frequency of RR

$2pq=$ frequency of Rr

$q^{2}=$ frequency of rr

The question is what is the frequency of heterozygotes, or, what is the value of 2pq.

We know that RR+Rr is 575 individuals in a population of 1000, or 0.575.

In other words:

$p^{2}+2pq=0.575$

So, it is possible to find $q^{2}$ :

$q^{2}= 1-2pq-p^{2} \\q^{2}=1-(0.575)\\q^{2}=0.425$

Now, there are two alleles in the population, so the following will be true:

$p+q=1$

It is possible to find q (the frequency of allele r) and p (the frequency of allele p):

$q=\sqrt{q^{2} }\\ q=\sqrt{0.425} \\q=0.652$

Therefore:

$p=1-q\\p=1-0.652\\p=0.348$

Now, the frequency of heterozygotes or 2pq is:

$2pq=2*0.652*0.348\\2pq=0.45$

7 0

3 years ago

Are plasmids membrane bound organelles

Hunter-Best [27]

The answer to that is yes!

4 0

4 years ago

How does tuberculosis(tb) evade the human immune system?

storchak [24]

Airborne is the most common.

6 0

3 years ago

A true breeding line of green pod pea plants is crossed with a true-breeding line of yellow pod plants. All of their offspring h

andre [41]

Answer:

green is the dominant trait and yellow would only be found in the second generation when 2 passive yellow genes can come together a green or yellow or green w green trait will always be green a pea can only be yellow with 2 recessive yellow genes

Explanation:

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3 years ago

Write characterize progression of infectious disease.

vlada-n [284]

Answer:

* Infectious disease management depends on precise portrayal of disease progression so transmission can be forestalled. Gradually progressing infectious diseases can be hard to characterize because of a latency period between the time an individual is infected and when they show clinical signs of disease.

* Defining directions through sickness states from infection to clinical illness can assist researchers with creating control programs dependent on focusing on individual infection state, possibly decreasing both progression and creating misfortunes because of the illness.

Explanation:

Gradually progressing infectious diseases are hard to characterize in light of the fact that they are frequently connected with an inactivity period between the time an individual is infected and when they give clinical indications or side effects of illness.

To successfully control infectious diseases, it is paramount to see how the disease progresses.

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3 years ago