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Alexxandr [17]
3 years ago
11

Is there a relationship between the area and the perimeter of a rectangle

Mathematics
1 answer:
maksim [4K]3 years ago
3 0
Well, an area and perimeter have formula's. The formula of area is length times width. The formula of perimeter is to basically length plus length plus width plus width. For instance, let's say the rectangles width is 5 and length is 6. So you do 5 plus 5 which is 10 and then 6 plus 6 which is 12. And then, 12 plus 10 equals 22. So the perimeter would be 22. If you were to find the area, you would do 6 times 5 and the area would be 30.
I hope this helps :)
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The hand spans, to the nearest cm, of some students in a class are shown below: 19, 22, 21, 15, 18, 22, 17, 19, 16, 21, 19, 18,
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Your Answer is D, delete 1 dot on 21.
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2 years ago
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Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and
Monica [59]

Step-by-step explanation:

We have got the lines :

y=ax+b\\y=cx+d

Both lines intercept the x-axis in the point :

I = (i_{1} ,i_{2})

In all point from x-axis the y-component is equal to 0.

I=(i_{1},o)

We replace the I point in the lines equations:

0=a(i_{1})+b \\0=c(i_{1})+d

From the first equation :

0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}

From the second equation :

0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}

Then i_{1}=i_{1}

Finally :

\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0
3 years ago
What is the x-value in the solution to this system of linear equations?
ASHA 777 [7]

Answer:

  4

Step-by-step explanation:

The y-variable can be eliminated by adding 3 times the first equation to the second:

  3(2x -y) +(x +3y) = 3(11) +(-5)

  7x = 28 . . . .  simplify

  x = 4 . . . . . . . divide by 7

_____

Using Cramer's Rule, you can also find the x-value. The math is not so different.

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2 years ago
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NISA [10]

Answer:

Step-by-step explanation:

Area of the good part= area of whole roof - area of bad part

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Area of good part =(x+12)²-x²

A= {(x+12)(x+12)} - x²

A = (x²+12x+12x+144) -x²

Open the bracket and rearrange the equation

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5 0
2 years ago
Please help, I need this quickly. Fairly easy, help pleasee
ahrayia [7]
-4x-3y-9=0
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_|_   m2  = -1/m1= 3/4

2x+4y-3=0
 ||     m1= -2/4= -1/2
_|_   m2= 2

12x-y-17=0
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  _|_ m2 = -1/12

x-y=0
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_|_ m2= -1

8x - 3y - 2=0
||     m1= -8/-3= 8/3
 _|_ m2 = -3/8

-2x + y - 5=0
||    m1= -(-2)/1=2
_|_ m2= -1/2



3 0
3 years ago
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