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2 years ago

Find the domain and range of the relation (-8,2),(6,-7),(-8,11),(10,5)

Mathematics

2 answers:

My name is Ann [436]2 years ago

7 0

Answer:

Domain{ -8,9,10} Range {2, -7,11,5}

Step-by-step explanation:

VARVARA [1.3K]2 years ago

5 0

Answer:

domain:2,-7,11,5

range:-8,6,-8,10

to explain more the domain would be your independent variable (y) and the range would be your dependent variable (x)

hope I helped

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What is the value of the expression below?<br> (V9)2 +10

Wittaler [7]

to find the value of this expression, it would be easiest to use the distributive property.

(V9)2 +10

= 18V+90V

= 108V

- cherry :)

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2 years ago

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(-2, 2), y=3x - 5 distance

Andrews [41]

Answer:

If you are using slope intercept it is incorrect

Step-by-step explanation:

For the first part y is 2 so using y=Mx+b it’s 2=-6-5 which is not correct

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2 years ago

A microorganism is a pathogen that _______

sergij07 [2.7K]

Answer:

A. can cause disease

Step-by-step explanation:

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2 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$

Substitute point (1, -1) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(1.-1) \implies a(1-h)^2+k &=-1\\a(1-2h+h^2)+k &=-1\\a-2ah+ah^2+k &=-1\\\implies a-2ah-4&=-1\\a(1-2h)&=3\end{aligned}$

Equate to find h:

$\begin{aligned}\implies a(1+h) &=a(1-2h)\\1+h &=1-2h\\3h &=0\\h &=0\end{aligned}$

Substitute found value of h into one of the equations to find a:

$\begin{aligned}\implies a(1+0) &=3\\a &=3\end{aligned}$

Substitute found values of h and a to find k:

$\begin{aligned}\implies ah^2+k&=-4\\(3)(0)^2+k &=-4\\k &=-4\end{aligned}$

Therefore, the equation of the parabola in vertex form is:

$\implies y=3(x-0)^2-4=3x^2-4$

So the vertex of the parabola is (0, -4)

5 0

2 years ago

Read 2 more answers

Given -8(x-3)=-32 prove x=7

AleksAgata [21]

Step-by-step explanation:

Plug x in :

-8(7-3) = -32

Distribute :

-56 - (-24) = -32

Subtract :

-32 = -32

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2 years ago