If it is ....
![3 {x}^{2} - 2x + 1 =](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%202x%20%2B%201%20%3D%20)
The coefficient of x² is (( 3 ))
& the coefficient of x is (( -2 ))
_________________________________
If it is .....
![3x - 2x + 1](https://tex.z-dn.net/?f=3x%20-%202x%20%2B%201)
![x + 1](https://tex.z-dn.net/?f=x%20%2B%201)
The coefficient of x² is (( zero 0 ))
& the coefficient of x is (( 1 ))
Answer:
1(q). 4 x (58 x 25) = 4 x (25 x __) = (__ x __) x 58 = ____
1(a). this problem cannot be solved
2(q). (293 x 50) x 20 = 293 x (50 x __)
2(a). (picture)
There are 50 different possible debating teams that could be selected as obtained using COMBINATION.
Since there are EQUAL number of juniors and seniors ;
Then we have 5 of each.
Here, the order of arrangement DOES NOT matter, Hence, we use COMBINATION
since the team MUST contain 4 SENIORS and 2 JUNIORS
4 Seniors from 5 = 5C4 = 5
2 Juniors from 5 = 5C2 = 10
Hence, (5C4 * 5C2) = 5 * 10 = 50
Hence, there are 50 different possible debating teams that could be selected.
Learn more :
brainly.com/question/8018593
Answer:
Step-by-step explanation:
concentration = amount of salt/solution
A) Initial concentration= 90/1000 = 0.09
Q = quantity of salt
Q(0) = 90 kg
Inflow rate = 8 l/min
Outflow rate = 8 l/min
Solution = 1000 L at any time t.
Salt inflow = 0.045 * 8 per minute
= 0.36 kg per minute
This is mixed and drains from the tank.
Outflow = ![\frac{Q(t)}{1000}](https://tex.z-dn.net/?f=%5Cfrac%7BQ%28t%29%7D%7B1000%7D)
Thus rate of change of salt
Q'(t) = inflow - outflow = ![0.36-\frac{Q(t)}{1000} \\=\frac{360-Q(t)}{1000}](https://tex.z-dn.net/?f=0.36-%5Cfrac%7BQ%28t%29%7D%7B1000%7D%20%5C%5C%3D%5Cfrac%7B360-Q%28t%29%7D%7B1000%7D)
Separate the variables and integrate
![\frac{1000dQ}{360-q(t)} =dt\\-1000 ln |360-Q(t)| = t+C\\ln |360-Q(t)| = -0.001+C'\\360-Q(t) = Ae^{-0.001t} \\Q(t) = 360-Ae^{-0.001t}](https://tex.z-dn.net/?f=%5Cfrac%7B1000dQ%7D%7B360-q%28t%29%7D%20%3Ddt%5C%5C-1000%20ln%20%7C360-Q%28t%29%7C%20%3D%20t%2BC%5C%5Cln%20%7C360-Q%28t%29%7C%20%3D%20-0.001%2BC%27%5C%5C360-Q%28t%29%20%3D%20Ae%5E%7B-0.001t%7D%20%5C%5CQ%28t%29%20%3D%20360-Ae%5E%7B-0.001t%7D)
Use the fact that Q(0) = 90
90 = 360-A
A = 270
So
![Q(t) = 360-270e^{-0.001t}](https://tex.z-dn.net/?f=Q%28t%29%20%3D%20360-270e%5E%7B-0.001t%7D)
B) Q(t) = 360-270e^-0.004 = 91.07784
C) When t approaches infinity, we get
Q(t) tends to 360
So concentration =360/1000 = 0.36
Answer:
|-15| is 15
Step-by-step explanation: