Answer:
10626 different arrangements
Step-by-step explanation:
As we have a total of 23 students and we want to form groups of 3, where the order of the 3 students matters, we can solve this problem using a permutation of 23 choose 3.
The formula for a permutation of n choose p is:
P(n,p) = n! / (n-p)!
So, using n = 23 and p = 3, we have:
P(23,3) = 23! / (23-3)! = 23! / 20! = 23 * 22 * 21 = 10626
So we have a total of 10626 different arrangements of first, second and third place.
Here a = 2, b = -2, c = -1
b^2-4ac = (-2)^2 - 4(2)(-1)
= 4 +8
= 12
The answer is 42 in each pile
Alright so, the angle AHI and J are actually the same. So they're both going to be 63 degrees
Knowing that, now you have to find the 3rd angle
All triangles angles add up to 180
63+45+x=180
108+x=180
-108 -108
72=x
