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nignag [31]
3 years ago
6

PLEASE ANSWER RIGHT AWAY! What the LCM of 2, & 5

Mathematics
2 answers:
Mumz [18]3 years ago
8 0
10 is the lcm of those to numbers
kaheart [24]3 years ago
5 0
2,4,6,8,10
5,10

So ten is the lcm.
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Answer quickly please I really need this answer right now
erastova [34]

Answer:

Answer Choice A (8, eight)

Step-by-step explanation:

To begin, add all of the marbles together. When finished, the answer should be 20. Because the variable 20 equals 100, you divide 4 by 100. You will get 0.04 as a result. This multiplied by 20 equals 8. Finally, the answer is A.

8 0
2 years ago
A toxic radioactive substance with the density of 4 mg/cm² is detected in the been detected in the ventilating ducts that was us
Kruka [31]
The formula for half-life is:

A = P(0.5)^{t/h}

A is the amount remaining, P is the initial amount, t is the time that has passed, and h is the half-life of the substance.  Plug in the values that you know and solve:

4 = P(0.5)^{35/20} \\ \\ 4 = P(0.5)^{1.75} \\ \\ P = \frac{4}{0.5^{1.75}} \\ \\ P \approx 13.4543426441

Rounded to the nearest whole number, the density of the substance was about 13<span>mg / cm².</span>
8 0
3 years ago
Simplify: 4 (3y +x) please show your work
Yakvenalex [24]

Answer:

12y+4x

Step-by-step explanation:

Multiply 4*3y and 4*x

Distributive property

7 0
3 years ago
Use the information to find the value cot 0 =
hjlf

The tangent function is given by:

\tan (\theta)=\frac{opposite}{_{\text{ }}adjacent}=\frac{5}{12}

Since the angle is in the 3rd quadrant the opposite side and the adjacent side are negative. So, the cotangent function is given by:

\cot (\theta)=\frac{1}{\tan (\theta)}=\frac{adjacent}{_{\text{ }}opposite}=\frac{-12}{-5}=\frac{12}{5}

Answer:

12/5

8 0
1 year ago
Please help me answer these in your own words!!!
liubo4ka [24]

6. any thang less than 90 degress

7. only 90 degress

8.any thang above 90 but not 180

9. only 180

10. the sum of 2 angels has to make 90 degress

11. the sum of 2 angles has to make 180 degress

4 0
3 years ago
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