Answer:
A. AgNO₃ + NaCl —> AgCl + NaNO₃
B. Mg(NO₃)₂ + 2KOH —> 2KNO₃ + Mg(OH)₂
C. 3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + 3LiNO₃
Explanation:
The equation given in the question above can be balanced as follow.
A. AgNO₃ + NaCl —> AgCl + NaNO₃
The above equation is already balanced.
B. Mg(NO₃)₂ + KOH —> KNO₃ + Mg(OH)₂
There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 2 before KOH as shown below:
Mg(NO₃)₂ + 2KOH —> KNO₃ + Mg(OH)₂
There are 2 atoms of K on the left side and 1 atom on the right side. It can be balance by writing 2 before KNO₃ as shown below:
Mg(NO₃)₂ + 2KOH —> 2KNO₃ + Mg(OH)₂
Thus, the equation is balanced.
C. LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + LiNO₃
There are 3 atoms of H on the right side and 1 atom on the left side. It can be balance by writing 3 before LiOH as shown below:
3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + LiNO₃
There are 3 atoms of Li on the left side and 1 atom on the right side. It can be balance by writing 3 before LiNO₃ as shown below:
3LiOH + Fe(NO₃)₃ —> Fe(OH)₃ + 3LiNO₃
Thus, the equation is balanced.
