D) 250l
Explanation :
250,000/1000
I don't know what the problem is, but here are some rues to help you out:
- All non-zero figures are significant
- When a zero falls between non-zero digits, that zero is significant.
- When a zero falls after a decimal point, that zero is significant.
- When multiplying and dividing significant figures, the answer is limited to the number of sig figs equal to the least number of sig figs in the problem.
- When adding and subtracting, the answer is limited to the number of decimal places in the number with the least number of decimal places.
Answer:
It is 1.76 tons under the weight limit.
Explanation:
12.65
-10.89
= 1.76
Answer:
27.3 kJ/mol
Explanation:
Step 1: Given data
- Temperature 1 (T₁): 298 K
- Vapor pressure 1 (P₁): P₁
- Temperature 2 (T₂): 318 K
- Vapor pressure 2 (P₂): 2 P₁
Step 2: Calculate the enthalpy of vaporization of this liquid
We will use the Clausius–Clapeyron equation.
ln (P₂/P₁) = -ΔHvap/R × (1/T₂ - 1/T₁)
ln 2 = -ΔHvap/(8.314 J/K.mol) × (1/318 K - 1/298 K)
ΔHvap = 2.73 × 10⁴ J/mol = 27.3 kJ/mol