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charle [14.2K]
3 years ago
12

4Hg(OH)2+ H3PO4 —> Hg3(PO4)2 + 5H20

Chemistry
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

Hi. im an online tutor and i ca help you with all your assignments . check out our wesite https://toplivewriters.com

Explanation:

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What volume will 1000 grams of nitrogen dioxide occupy at 380 mmHg at 0°C
KiRa [710]

0.69(78)Explanation:

7 0
3 years ago
The melting point of your product is 10 degrees lower than the expected one. What conclusion can you make about the purity of yo
DanielleElmas [232]

Answer:

The product is significantly impure

Explanation:

In order to test for the purity of a specific sample that was synthesized, the melting point of a compound is measured. Basically speaking, the melting point identifies how pure a compound is. There are several cases that are worth noting:

  • if the measured melting point is significantly lower than theoretical, e. g., lower by 3 or more degrees, we conclude that our compound contains a substantial amount of impurities;
  • wide range in the melting point indicates impurities, unless it agrees with the theoretical range.

Since our compound is even 10 degrees Celsius lower than expected, it indicates that the compound is significantly impure.

5 0
3 years ago
Energy from sources that are constantly being formed is non-renewable energy.
Alisiya [41]
If they are constantly being formed then, they are called renewable energy. So the statement above is false. B.


6 0
3 years ago
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
Please Help! Thank You
Ivanshal [37]

Explanation:

the answer is true because I had this question and got it right

3 0
3 years ago
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