Answer:
Ka = 6.02x10⁻⁶
Explanation:
The equilibrium that takes place is:
We <u>calculate [H⁺] from the pH</u>:
- [H⁺] =
Keep in mind that [H⁺]=[A⁻].
As for [HA], we know the acid is 0.66% dissociated, in other words:
We <u>calculate [HA]</u>:
Finally we <u>calculate the Ka</u>:
- Ka =
![\frac{[9.12x10^{-4}]*[9.12x10^{-4}]}{[0.138]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B9.12x10%5E%7B-4%7D%5D%2A%5B9.12x10%5E%7B-4%7D%5D%7D%7B%5B0.138%5D%7D)
= 6.02x10⁻⁶
Answer:
The 
solution has a higher osmotic pressure and higher boiling point than LiCl solution.
Explanation:
As concentrations of two aqueous solutions are same therefore we can write:
, 
and 
where 
, 
and 
are lowering of vapor pressure, elevation in boiling point and osmotic pressure of solution respectively. 
is van't hoff factor.
= total number of ions generated from dissolution of one molecule of a substance (for strong electrolyte).
Here both and LiCl are strong electrolytes.
So, 
and 
Hence, lowering of vapor pressure, elevation in boiling point and osmotic pressure will be higher for solution.
Therefore the solution has a higher osmotic pressure and higher boiling point than LiCl solution.
D. details about what happening
Through absorbing nutrients and matter and the releasing new matter, usually in the form of CO2<span />
