Help me by please this is kinda hard for my child and I forgot it
1 answer:
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We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.
Using inverse sine or arcsin, we will get:
Upon rounding to nearest degree, we will get:
Therefore, the measure of angle J is approximately 24 degrees.
Here's the answer, using the quadratic formula
To make it much easier, it should be converted to the slope-intercept form
y = mx + b
To do so, 14x + 34y = 1 turns to:
34y = -14x + 1
Divide both sides by 34:
Simplified:
Answer:
Here is the graph:
y = mx + b
To do so, 14x + 34y = 1 turns to:
34y = -14x + 1
Divide both sides by 34:
Simplified:
Answer:
Here is the graph: