2 years ago

Write ground-state electron configurations for Na+ using a noble gas core abbreviation.

Chemistry

1 answer:

pickupchik [31]2 years ago

4 0

It's [Ne] because one electron is taken away (since its Na+ not Na).

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PLEASE HELP ASAP

Leni [432]

Answer:

the answer is B

Explanation:

the answer is B

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2 years ago

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A compound ‘X’ is used for drinking, has pH =7.Its acidified solution undergoes decomposition in presence of electricity to prod

umka21 [38]

Answer:

X = Water (H2O) ; Y = Hydrogen ; Z = Oxygen

Explanation:

2(H2O) -------> 2H2 + O2

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2 years ago

15. Which characteristic of a substance will NOT

Andrej [43]

Boiling point. Hope this helps

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1 year ago

When an acid solution exactly neutralizes a base

o-na [289]

Answer:a weak acid and a weak base

Explanation:

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2 years ago

What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl

Kitty [74]

Answer:

$\large \boxed{\text{0.012 mol}}$

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL: 70.

c/mol·L⁻¹: 0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

$\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}$

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

$\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }$

3 0

2 years ago