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Dmitry_Shevchenko [17]
3 years ago
11

I NEED HELP PEOPLE!!!! WILL GIVE BRAINLIEST!!!!

Mathematics
1 answer:
Sauron [17]3 years ago
6 0

Answer:

L(2,4)   M(3,1)   N(0,4)

Step-by-step explanation:

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What are the solutions of the system 7x + 3y=-3 and y= -2*?
mafiozo [28]

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1    (0,-1) is solution

         when x=3 , 21+3y=-3,  3y= -3-21= -24

                                                    y= -8                  (3,-8) is also solution

8 0
3 years ago
Michael walks his black lab 6 2/3 miles every week. If he walks his dog every Monday, Wednesday, Friday, and Sunday. How many mi
Elenna [48]

Answer: 1.7 miles

Step-by-step explanation:

dog is walked four times a week

6 2/3 miles in all

6 2/3 divided by 4 = 1.66666667

1.66666667 rounded to nearest tenth = 1.7

6 0
3 years ago
Derivative, by first principle<br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28%20%5Csqrt%7Bx%20%7D%20%29%20" id="TexFormula1"
vampirchik [111]
\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}h

Employ a standard trick used in proving the chain rule:

\dfrac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\cdot\dfrac{\sqrt{x+h}-\sqrt x}h

The limit of a product is the product of limits, i.e. we can write

\displaystyle\left(\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan x}{\sqrt{x+h}-\sqrt x}\right)\cdot\left(\lim_{h\to0}\frac{\sqrt{x+h}-\sqrt x}h\right)

The rightmost limit is an exercise in differentiating \sqrt x using the definition, which you probably already know is \dfrac1{2\sqrt x}.

For the leftmost limit, we make a substitution y=\sqrt x. Now, if we make a slight change to x by adding a small number h, this propagates a similar small change in y that we'll call h', so that we can set y+h'=\sqrt{x+h}. Then as h\to0, we see that it's also the case that h'\to0 (since we fix y=\sqrt x). So we can write the remaining limit as

\displaystyle\lim_{h\to0}\frac{\tan\sqrt{x+h}-\tan\sqrt x}{\sqrt{x+h}-\sqrt x}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{y+h'-y}=\lim_{h'\to0}\frac{\tan(y+h')-\tan y}{h'}

which in turn is the derivative of \tan y, another limit you probably already know how to compute. We'd end up with \sec^2y, or \sec^2\sqrt x.

So we find that

\dfrac{\mathrm d\tan\sqrt x}{\mathrm dx}=\dfrac{\sec^2\sqrt x}{2\sqrt x}
7 0
3 years ago
What is the quotient of the following rational expression?<br> x^3+3x^2-4x+5/x^2-2
Law Incorporation [45]

Answer:

Here:

Step-by-step explanation:

7 0
1 year ago
The winner of a gymnastics competition scored a total of 22.1 points. She won by 0.676 points.
weqwewe [10]

Answer:

21.424

Step-by-step explanation:

22.1 - 0.676 = 21.424

im not sure if it is correct but i think its like this

7 0
3 years ago
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