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MAXImum [283]
3 years ago
12

If the sin of angle x is 4 over 5 and the triangle was dilated to be two times as big as the original, what would be the value o

f the sin of x for the dilated triangle?
what is the equation for this I cant figure out using sin,cos, and Tan
Mathematics
1 answer:
sergey [27]3 years ago
7 0
In a dilation the angle doesn't change so the sin x will stay 4/5. cos x is 3/5 and tan x is 4/3.
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You place the spring vertically with one end on the floor. You then drop a book of mass 1.50 kg onto it from a height of 0.900 m
Alex777 [14]

Answer:

The value of the maximum distance the spring will be compressed  

x = 0.143 m= 14.3 cm

Step-by-step explanation:

Given data

Mass m = 1.5 kg

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y = h + x

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mg y= \frac{1}{2} k x^{2}

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8 0
3 years ago
1. Suppose that 35% of all patients admitted to a hospital's intensive care unit (ICU) have high blood pressure, 42% have some s
Lelechka [254]

Answer:

a) 65%

b) 28.57%

Step-by-step explanation:

Suppose that 35% of all patients admitted to a hospital's

intensive care unit have high blood pressure, 42% have some sort of infection, and 12% have both problems. Probabilities estimated from the data in ICU Admissions. (10POINTS)

 (a)  Find the probability that a randomly chosen patient in this ICU has either high blood pressure or an infection.

 (b)  Find the probability that a patient admitted to the ICU has high blood pressure given that an infection is present.

Solution:

Let H represent the people with high blood pressure and I represent the people with infection.

P(H) = 35% = 0.35, P(I) = 42% = 0.42, P(H ∩ I) = 12% = 0.12

Those with only high blood pressure = P(H ∩ I') = P(H) - P(H ∩ I) = 0.35 - 0.12 =0.23

Those with only infection = P(H' ∩ I) = P(I) - P(H ∩ I) = 0.42 - 0.12 =0.30

a) probability that a  patient has either high blood pressure or an infection = P(H ∪ I)

P(H ∪ I) = P(H ∩ I') + P(H' ∩ I) + P(H ∩ I) = 0.23 + 0.3 + 0.12 = 0.65 = 65%

b) probability that a patient has high blood pressure given that an infection is present = P(H / I)

P(H / I) = P(H ∩ I) / P(I) = 0.12 / 0.42 = 0.2857 = 28.57%

4 0
3 years ago
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