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Lapatulllka [165]

3 years ago

8

The ratio of backslappers to wallflowers at the political convention was 20 to I. If there were 460 backslappers, how many wallf

lowers were there?

1 answer:

Alja [10]3 years ago

3 0

Answer:

x =23

Step-by-step explanation:

We can use a ratio to solve

20 backslappers 460 backslappers

------------------------- = ------------------------------

1 wallflower x wallflowers

Using cross products

20*x = 460*1

Divide each side by 20

20x/20 = 460/20

x =23

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tankabanditka [31]

7.C I think is the answer

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3 years ago

You are planning a skating party at a rink that charges a basic fee of $6.00 and $6.50 per person for catered parties. You don’t

Alekssandra [29.7K]

Answer:

y = 6.50x + 6 or 71 = 6.50x + 6

10 people are the max you can invite

Step-by-step explanation:

We have the simple equation

y = 6.50x + 6

6.50x because it it per person

6 because it is a flat one time charge

We want the max to be 71 so that will be our y

71 = 6.50x + 6

We are now going to solve for x

65 = 6.5x

x = 10

Hope it helps! (:

4 0

2 years ago

State whether the data described below are discrete or continuous, and explain why.

enot [183]

Answer:

A. The data are continuous because the data can take on any value in an interval.

Step-by-step explanation:

A continuous data is any data set having infinitely many possible values and those values cannot be counted, meaning they are uncountable. Any quantity such as height, volume, weight, density, length, pressure, temperature, speed, distance, time are generally a continuous data.

Hence, the exact heights of different elephants represents a continuous data because the data can take on any value in an interval.

On the other hand, a discrete data is any data set in which the number of possible values are either finite or countable. Thus, a discrete data can only take on specific values. For example, the value of a fair die, number of sweets in a jar, number of eggs in a crate etc.

6 0

3 years ago

4. An ice cream shop wants to design a super straw to serve with its extra thick milkshakes that is double both the width and th

Andre45 [30]

Answer:

A. $\\ 0.50cm^{2}$ ; B. $\\ 5.03cm^{3}$ ; C. 19min

Step-by-step explanation:

<h3>First Step: Determine the size of the new straw</h3>

The size of the new straw is "double both the width and thickness of a standard straw". "A standard straw is 4mm in diameter and 0.5mm thick". So, the new straw is, then:

$\\ 2 * 4mm = 8mm$ or, equivalently, $\\ \frac{1cm}{10mm} * 8mm = 0.8cm$ (<em>Diameter</em>).

$\\ 2 * 0.5mm = 1mm$ or, equivalently, $\\ \frac{1cm}{10mm} * 1mm = 0.1cm$ (<em>Thickness</em>).

<h3>Second Step: Determine the cross-sectional area of the new straw</h3>

The cross-section area is "a section made by a plane cutting anything transversely, especially at right angles to the longest axis" <em>Cross-section</em> (2020), In Dictionary.com. Therefore, the area here is that of a circle:

$\\ A_{cross_{section}}= \pi * r^2$ ,

Where $\\ \pi = 3.1415926535897932384626....$ , and represents the ratio between a circle's circumference and its diameter, and <em>r</em> is the circle's radius or its diameter divided by 2.

Then, the area is:

$\\ A_{cross_{section}} = \pi * (\frac{0.8cm}{2})^2 = \pi * (0.4cm)^2= 0.502655cm^2$ , rounded to <em>the nearest hundredth</em>:

$\\ A_{cross_{section}} = 0.50cm^2$

<h3>Third Step: Determine the maximum volume of milkshake that can be in the straw at one time</h3>

The new straw is 10cm long and its cross-section is, approximately,

$\\ A_{cross_{section}} = 0.502655cm^2$

Since the straw is a cylinder, and the volume of a cylinder is:

$\\ V_{straw} = \pi * r^2 * h = A_{cross_{section}} * h$ , where <em>h</em> is the height of the straw. In this case is 10cm long.

So, <em>the maximum volume of milkshake that can be in the straw at one time</em> is the volume of the straw:

$\\ V_{straw} = A_{cross_{section}}*h = 0.502655cm^2 * 10cm = 5.02655cm^3$ , rounded to the <em>nearest hundredth</em>:

$\\ V_{straw} = 5.03cm^3$

<h3>Fouth Step: Determine the minimum amount of time that it will take Corbin to drink the milkshake</h3>

A large milkshake is 950mL, and we know that:

$\\ 1000mL = 1000cm^3 = 1L$

So,

$\\ 1mL = 1cm^3$ , therefore, $\\ 950mL = 950cm^3$

"Corbin withdraws the full capacity of a straw 10 times a minute" or Corbin withdraws:

$\\ 10*V_{straw} = 10*5.02655cm^3 = 50.2655cm^3$ every minute.

The large milkshake is $\\ 950cm^3$ . If Corbin withdraws $\\ \frac{50.2655cm^3}{min}$ , <em>the minimum amount of time that it will take him to drink the milkshake</em> is:

$\\ \frac{950cm^3}{\frac{50.2655cm^3}{min}} = \frac{950}{50.2655}*\frac{cm^3}{cm^3}*min = 18.8996min$ , since $\\ \frac{cm^3}{cm^3} = 1$ .

Rounded to the nearest minute, the minimum amount of time is 19min.

8 0

3 years ago

Help I need this for my class

erik [133]

18 is the value hope it helps

4 0

3 years ago

Read 2 more answers