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DENIUS [597]
3 years ago
10

How many times does 16 go into 20

Mathematics
2 answers:
Anarel [89]3 years ago
5 0
The answer to that is easy, first you divide 20 by 16, and then get the answer which is 1.25. Then you take the fraction away from that so it only leaves the whole number, which is 1. Therefore the answer is 1, unless you need the fraction version then it is 1 1/5.
Deffense [45]3 years ago
3 0
16 only goes into 20 once
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F ( x ) = x + 4
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Describe the equation 2x + 15 = 23 + x in words.
AveGali [126]

Answer:

x = 8

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x = 8

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x = 1/4

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Step-by-step explanation:

(For all instances of number, let it be x)

Double the sum of a number and 15. The result is the same as the product of 23 and the number.

2x + 15 = 23 + x

2x - x + 15 = 23 + x - x

x + 15 = 23

x + 15 - 15 = 23 - 15

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Multiply a number by 15 and add 2. The result is the same as the sum of 23 and the number.

15x + 2 = 23 + x

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x = 21/14

Double a number and add 15. The result is the same as the sum of 23 and the number.

2x + 15 = 23 + x

x + 15 = 23

x = 8

Double a number and add 15. The result is the same as the product of 23 and the number. (This time we will move the x to the other side as the right side has a larger x than the left side)

2x + 15 = 23x

15 = 21x

x = 15/21

Multiply a number by 15 and add 2. The result is the same as the product of 23 and the number.

15x + 2 = 23x

2 = 8x

2/8 = x

x = 1/4

Double the sum of a number and 15. The result is the same as the sum of 23 and the number.

2(x + 15) = 23 + x

2x + 30 = 23 + x

x + 30 = 23

x = 7

6 0
3 years ago
14)
Evgesh-ka [11]

Answer: 10

Step-by-step explanation: The diameter is twice the radius

3 0
2 years ago
The circumference of a circle is 11pi inches. What is the area, in square inches, of the circle? Express your answer in terms of
Eva8 [605]

\bf \textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=11\pi \end{cases}\implies 11\pi =2\pi r\implies \cfrac{11\pi }{2\pi }=r\implies \boxed{\cfrac{11}{2}=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \qquad \implies A=\pi \left( \cfrac{11}{2}\right)^2\implies A=\pi \left( \cfrac{11^2}{2^2}\right)\implies A=\cfrac{121\pi }{4}

4 0
4 years ago
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