Assume that when adults with smartphones are randomly selected, 35% use them in meeting or classes. if 7 adults smartphones user s are randomly selected, find the probability that exactly 4 of them use their smartphones in meeting or classes. The probability is
1 answer:
This is a binomial probability problem p = 0.35 = chance of picking 1 person who uses smartphones during meeting/class n = 7 = sample size k = 4 = target number of people who use their smartphone Compute nCk = 7C4 using the nCr combination formula nCr = (n!)/(r!*(n-r)!) 7C4 = (7!)/(4!*(7-4)!) 7C4 = (7*6*5*4!)/(4!*3!) 7C4 = (7*6*5)/(3!) 7C4 = (210)/(6) 7C4 = 35 Use this coefficient to find the binomial probability B(k) = binomial probability for input k B(k) = (nCk)*(p^k)*(1-p)^(n-k) B(4) = (7C4)*(0.35^4)*(1-0.35)^(7-4) B(4) = 35*(0.35^4)*(0.65)^3 B(4) = 0.144238 So the approximate answer is 0.144238 This value is accurate to 6 decimal places
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