Answer:
Explanation:
A chemical bond is a lasting attraction between atoms, ions molecules that enables the formation of chemical compound.
<u>Answer:</u> The correct answer is 
<u>Explanation:</u>
We are given:
Moles of hydrogen gas = 4 moles
As, oxygen is given in excess. Thus, is considered as an excess reagent and hydrogen is considered as a limiting reagent because it limits the formation of products.
For the given chemical equation:
By Stoichiometry of the reaction:
2 moles of hydrogen produces 2 moles of water molecule.
So, 4 moles of hydrogen will produce = 
of water.
Hence, the correct answer is
Conservation of mass is the underlying principle of balancing equation. When we balance equation, this means that we acknowledge that before and after the chemical reaction, the elements are conserved. To balance the chemical equation, we add coefficients before each reactant and product. Here are the following answers:
Reaction 1:
<span>2Al
3ZnCl2
3Zn
2AlCl3
Reaction 2:
</span><span>4NH3
3O2
2N2
6H2O</span>
10. is C or gas and 11. is B liquid.
Answer: d. Remove one-half of the initial CaCO3.
Explanation: Le Chatelier's principle states that changes on the temperature, pressure, concentration and volume of a system will affect the reaction in an observable way. So in the reaction above:
A decrease in temperature will shift the equilibrium to the left because the reaction is exothermic, which means heat is released during the reaction. In other words, when you decrease temperature of a system, the equilibrium is towards the exothermic reaction;
A change in volume or pressure, will result in a production of more or less moles of gas. A increase in volume or in the partial pressure of CO2, the side which produces more moles of gas will be favored. In the equilibrium above, the shift will be to the left.
A change in concentration will tip the equilibrium towards the change: in this system, removing the product will shift the equilibrium towards the production of more CaCO3 to return to the equilibrium.
So, the correct answer is D. Remove one-half of the initial CaCO3.
