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Semenov [28]
3 years ago
8

PLEASE HELP ME What answer is it?

Chemistry
1 answer:
77julia77 [94]3 years ago
8 0
The answer is A if the temperature increases, then it’s volume will also increase
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Helpppp fasttttttttttttttt Choose the best word to complete the sentence.
Lapatulllka [165]

Answer:

equilateral (B)

Explanation:

it is the only word which relates to triangles and their shape - plus, its logical and makes sense.

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Two students are trying to figure out the Calories per gram of potato chips. They burn part of the potato chip and feel the heat
kakasveta [241]

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ok

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2 years ago
Which of the following can form a hydrogen bond with the HF molecule?
Lostsunrise [7]

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helium

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6 0
3 years ago
What is the enthalpy of formation (?H?f) of NaHCO3(s) from its constituent elements.
vova2212 [387]

Answer:

Enthalpy of formation = -947.68KJ/mol

Explanation:

Enthalpy of formation is the heat change when one mole of a substance is formed from its element in its standard states and in standard conditions of temperature and pressure. it may be positive or negative, if positive, it is an endothermic reaction where the heat content of the product is greater than that of the reactants, and if negative, it is exothermic reaction - where the heat content of the reactants is greater than the products. the enthalpy of formation is measured in KiloJoule/Moles (KJ/Mole).

From the value of the enthalpy of formation of NaHCO3, it shows that the reaction is exothermic, that is the formation of NaHCO3 from its constituents elements. As such, the heat content of the reactants is greater than the products.

The step by step explanation is shown in the attachment.

7 0
3 years ago
Read 2 more answers
In laboratory experiment, a NOVDEC Student was
Ede4ka [16]

Answer:

i. Molar mass of glucose = 180 g/mol

ii. Amount of glucose = 0.5 mole

Explanation:

<em>The volume of the glucose solution to be prepared</em> = 500 cm^3

<em>Molarity of the glucose solution to be prepared</em> = 1 M

i. Molar mass of glucose (C_1_2H_6O_6) = (6 × 12) + (12 × 1) + (6 × 16) = 180 g/mol

ii.<em> mole = molarity x volume</em>. Hence;

amount (in moles) of the glucose solution to be prepared

                 = 1 x 500/1000 = 0.5 mole

3 0
2 years ago
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