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3 years ago

PLEASE HELP ME What answer is it?

Chemistry

1 answer:

77julia77 [94]3 years ago

8 0

The answer is A if the temperature increases, then it’s volume will also increase

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Explain with example that law of conservation of mass is valid for chemical reactions.

Hoochie [10]

The law of conservation of mass states that in a closed system, the mass of the system cannot change over time. Look at our example of the candle in the closed room. ... If you massed the reactants oxygen and wax, it would equal the mass of the products water and carbon dioxide.

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3 years ago

As a train rushes away from a crossing, the pitch of its horn goes down because _____________________.

scoundrel [369]

Answer:

The awnser is b

Explanation:

The sound waves get smaller as the sound moves farther away, and since the sound waves are smaller, the sound is quieter. This is known as the Doppler effect.

5 0

3 years ago

Please help with this

tatyana61 [14]

A is getting pushed out
B is going in and out at the same rate
C is getting pulled in

8 0

3 years ago

A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

inn [45]

Answer:

$m_{steel}=54.47gSteel$

Explanation:

Hello,

In this case, one considers that the heat lost by the water is gained by the steel rod:

$\Delta H_{water}=-\Delta H_{steel}$

That in terms of masses, heat capacities and temperatures is:

$m_{water}Cp_{water}(T_F-T_{water})=-m_{steel}Cp_{steel}(T_F-T_{steel})$

Thus, solving for the mass of the steel rod, we obtain:

$m_{steel}=\frac{m_{water}Cp_{water}(T_F-T_{water})}{-Cp_{steel}(T_F-T_{steel})} \\\\m_{steel}=\frac{125mL*\frac{1g}{1mL}*4.18\frac{J}{g^oC} (22.00^oC-21.10^oC)}{-0.452\frac{J}{g^oC}*(2.00^oC-21.10^oC)} \\\\m_{steel}=54.47gSteel$

Best regards.

6 0

4 years ago

How many hydrogen atoms are in 5.10 mol of ammonium sulfide?

Drupady [299]

Answer:

2.46 × 10²⁵ atoms H

Explanation:

Avagadro's Number: 6.022 × 10²³

Step 1: Find formulas

Hydrogen - H

Ammonium Sulfide - (NH₄)₂S

Step 2: Use Dimensional Analysis

$5.10 \hspace{3} mol \hspace{3} (NH_4)_2S(\frac{8 \hspace{3} mol \hspace{3} H}{1 \hspace{3} mol \hspace{3} (NH_4)_2S})(\frac{6.02(10)^{23} \hspace{3} atoms \hspace{3} H}{1 \hspace{3} mol \hspace{3} H} )$ =

Step 3: Simplify

We have 3 sig figs.

2.45616 × 10²⁵ atoms H ≈ 2.46 × 10²⁵ atoms H

4 0

3 years ago