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3 years ago

Which is an element? A) alcohol B) sodium C) sugar D) water

Chemistry

2 answers:

hichkok12 [17]3 years ago

7 0

The answer is B, sodium is an element.

True [87]3 years ago

3 0

Sodium.
Hope this helps you out.

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For a hydrogen atom, which electronic transition would result in the emission of a photon with the highest energy? for a hydroge

vagabundo [1.1K]

The transitions which fall to the lowest principle position release the greatest energies. In this case, this would be the transition from the 5p to the 3s orbital (a Paschen transition).

Hope this helps!

6 0

2 years ago

Read 2 more answers

Consider the balanced equation below. 4NH3 + 3O2 --> 2N2 + 6H2O What is the mole ratio of NH3 to N2?

AURORKA [14]

The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

Therefore, the mole ratio of NH3 to N2 is 4:2 which can be simplified into 2:1

4 0

2 years ago

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Having been heated to 800 K , at some point the tank starts to leak. By the time the leak is repaired, the tank contains only ha

Liula [17]

Answer: The temperature of the gas reduced to 400K.

Explanation:

Stated that ; The pressure remains the same, that is initial and final pressure equals 1atm.

Applying Charles Law

$V1/T1 = V2/T2$

Initial volume V1 = 1

Final volume V2 = 1/2 (halved)

Initial temperature T1 =800K

Final temperature T2 = ?

(1/800) = (1/2)/T2

T2 = 800/2

T= 400K

Therefore, when the volume is halved, the temperature reduced also to half ( 400K)

3 0

2 years ago

Given the following data: Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39

nalin [4]

Answer:

ΔH° = -11 kj

Explanation:

Step 1: Data given

1) Fe2O3(s) + 3 CO(g) → 2 Fe(s) + 3 CO2(g) ΔH = −23 kJ

2) 3 Fe2O3(s) + CO(g) → 2 Fe3O4(s) + CO2(g) ΔH = −39 kJ

3) Fe3O4(s) + CO(g) → 3 FeO(s) + CO2(g) ΔH = +18 kJ

Step 2: The balanced equation

FeO + CO → Fe + CO2

Step 3: Calculate ΔH for the reaction FeO(s) + CO(g) → Fe(s) + CO2(g).

To get this equation, we need to combine the 3 equations

We have to multiply the third equation by 2.

2Fe3O4(s) + 2CO(g) → 6 FeO(s) + 2CO2(g) ΔH = +54 kJ

This equation we add to the second equation

3Fe2O3(s) + CO(g) + 2Fe3O4(s) + 2CO(g) → 2Fe3O4(s) + CO2(g) + 6FeO(s) + 2CO2 (g)

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

ΔH° = 2*18 + (-39) = 36 - 39 = -3 kJ

This new equation we will divide by 3

3Fe2O3(s) + 3CO(g) → 3CO2(g) + 6FeO(s)

Fe2O3(s) + CO(g) → CO2(g) + 2FeO(s)

ΔH° =-3/3 = -1 kJ

Now we will substract this new equation from the first equation

Fe2O3(s) + 3CO(g) - Fe2O3(s) - CO(g) → 2Fe(s) + 3CO2(g) -2FeO(s) - CO2(g)

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

ΔH° = -23kJ +1kJ

ΔH° = -22 kj

The next equation we will divide by 2

2CO(g) + 2FeO(s) → 2Fe(s) + 2CO2(g)

CO(g) + FeO(s) → Fe(s) + CO2(g)

ΔH° = -22kJ /2

ΔH° = -11 kj

7 0

2 years ago

Explain why the standard enthalpy of formation () for Cl2 (g) is zero, but its standard entropy is larger than zero.

Galina-37 [17]

The standard enthalpy of formation for chlorine is zero but the standard entropy is larger than 0 because it is the elemental state of chlorine.

The standard enthalpy of formation for chlorine is zero because cl2 is the elemental state of chlorine and it does not require any energy for the formation of the standard state of chlorine.

The entropy of any system cannot be negative. It can only be positive or zero.

The entropy of a system will become zero only at a absolute zero temperature.

That's why the entropy of chlorine in elemental state is more than zero because absolutely zero temperature can't be obtained.

To know more about entropy, visit,

brainly.com/question/6364271

#SPJ4

7 0

9 months ago