All categories

3 years ago

How can b^2+9b+14 be re-written?

1 answer:

3 0

$b^2+9b+14 =\\ \\=b^2+9b-2b + 2b +14 =\\ \\ =b^2+7b +2b +14 = \\ \\ = b(b+7)+2(b+7)=\\ \\=(b+7)(b+2) \\ \\ Answer: \ 4. ) \ (b+7)(b+2)$

You might be interested in

Identify sinJ as a fraction and as a decimal rounded to the nearest hundredth.

KiRa [710]

In the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

In trigonometry, for a right triangle, the sine (sin) of any angle θ is given as the ratio of its opposite side to the hypotenuse of the triangle, that is, sin θ = (opposite side)/(hypotenuse).

In the question, we are asked to find the trigonometric ratio, sin J, for the given right triangle JKL.

The side opposite to angle J is KL, which has a value of 3 units.

The hypotenuse of the given right triangle is JK, which has a value of 7.8 units.

Thus, sin J can be calculated as:

sin J = KL/JK = 3/7.8 = 5/13 = 0.39.

Thus, in the given right triangle, the trigonometric ratio, sin J has a fractional value of 5/13 and a decimal value of 0.39.

Learn more about trigonometric ratios at

brainly.com/question/20367642

#SPJ1

8 0

1 year ago

Explain how to find a measure of angle ACD without repositioning the protractor

MatroZZZ [7]

Answer:

60 degrees

Step-by-step explanation:

ACD and ACB are complementary angles. Find ACB=30 degrees. Subtract 30 from 90 degrees. ACD=60 degrees.

6 0

3 years ago

???????????????????????????

FinnZ [79.3K]

Answer:

y-(-20)=1(x-(-10))

Step-by-step explanation:

If you're really in college you should know this, but here's the explanation:

m= -9-(-20)

1-(-10)

= 11

m = 1

The equation is y-y^1=m(x-x^1)

Replace the y^1, m, and x^1 from the first point

You get y-(-20)=1(x-(-10))

Or simplify that into y+20=x+10

You can also simplify it more but I don't think you need that for that question

7 0

2 years ago

Round to the nearest tenth if necessary.

Andrei [34K]

Answer:

B) 25

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Identify

Point (-1, -8)

Point (-4, -4)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(-4--1)^2+(-4--8)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-3)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{9+16}$
[√Radical] Add: $\displaystyle d = \sqrt{25}$
[√Radical] Evaluate: $\displaystyle d = 5$