Because these are two consecutive numbers and the first integer is x, the second integer must be x+1 (it could be x-1 too, but here I'm going to solve the problem with x+1).
The sum of the two integers is 57, so we have:
x+ (x+1)= 57
⇒ (x+ x)+ 1= 57 (associative property)
⇒ 2x+ 1= 57
⇒ 2x= 57-1
⇒ 2x= 56
⇒ x= 56/2
⇒ x= 28
Since x= 28, the first integer is 28, and the second integer is:
x+1= 28+1= 29
The two numbers are 28 and 29.
Hope it helps.
To find the solutions to the system, we need to find exactly when one expression is equal to the other. We can do this by setting both of the right sides equal to each other, so that

Subtracting x+6 from either side, we find

factoring out an x+6:


The x-coordinates of our solutions will therefore be 6 and -6. Since the question only asks for the <em>x-coordinate</em> of the midpoint, we simply need to find the number exactly halfway between 6 and -6, which is 0.
K^10 is the answer you're looking for.
You take 4.84 x 10^8 times 7.2
Hi, the answer is A, 6.
When you have 2 negative signs like: 1-(-5), it turns into 1+(+5).
When you have to add a negative, like: 13+(-12), it turns into 13-(12)