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3 years ago

PLEASE HELP (Giving Good Points!)

Mathematics

1 answer:

Vinvika [58]3 years ago

7 0

Answer: q=16

Step-by-step explanation:

if we suppose q=16

(q+4)/2=10

$(16+4)/2=10\\20/2=10\\10=10$

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What is the slope between these two points? (2,5) (8, 12)

Minchanka [31]

Answer:

7/6

Step-by-step explanation:

y2-y1/x2-x1(slope formula)

plug in numbers

12-5=7

8-2=6

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3 years ago

To find the square root of a number, you must divide the number by 2. True False

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3 years ago

I don’t know how to find X or Y very urgent, need to figure this out how to solve plz help

Lena [83]

Answer:

x = 9

y = 9√3 = 15.6

Step-by-step explanation:

The triangle given is a right triangle, therefore:

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Adjacent = x

Thus:

Cos (60) = x/18

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3 years ago

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3 years ago

Read 2 more answers

At what point on the paraboloid y = x2 + z2 is the tangent plane parallel to the plane 3x + 2y + 7z = 2? (if an answer does not

Nikitich [7]

If $f(x, y, z) = c$ represent a family of surfaces for different values of the constant $c$ . The gradient of the function $f$ defined as $\nabla f$ is a vector normal to the surface $f(x, y, z) = c$ .

Given the paraboloid

$y = x^2 + z^2$ .

We can rewrite it as a scalar value function f as follows:

$f(x,y,z)=x^2-y+z^2=0$

The normal to the paraboloid at any point is given by:

$\nabla f= i\frac{\partial}{\partial x}(x^2-y+z^2) - j\frac{\partial}{\partial y}(x^2-y+z^2) + k\frac{\partial}{\partial z}(x^2-y+z^2) \\ \\ =2xi-j+2zk$

Also, the normal to the given plane $3x + 2y + 7z = 2$ is given by:

$3i+2j+7k$

Equating the two normal vectors, we have:

$2x=3\Rightarrow x= \frac{3}{2} \\ \\ -1=2 \\ \\ 2z=7\Rightarrow z= \frac{7}{2}$

Since, -1 = 2 is not possible, therefore there exist no such point on the paraboloid $y = x^2 + z^2$ such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2.

4 0

3 years ago