Answer:
Explanation:
A limiting reactant in a chemical reaction is one which puts limits on amount of product produced out of the reaction. The process of chemical reaction is stopped when the limiting reactant is fully used up.
Example:
Suppose you have
5 gram of oxygen and 10 gram of hydrogen to make any chemical product say y
since
amount of oxygen is only 5 gram thus, when all of 5 gram of oxygen will be used up then no further reaction will take place even though amount of hydrogen is present to react.
Thus, we can say that
oxygen is limiting the production of product y.
oxygen is fully used until the reaction stops.
Thus, in this case oxygen is limiting reactant.
Based on above discussion
the correct option for this problem is
a the reactant that is used up
Answer:
Explanation:
Heat lost by metal = mass x specific heat x fall in temperature
= 74 x S x ( 94 - 32 )
= 4588 S
heat gained by water = mass x specific heat x rise in temperature
= 120 x 1 x ( 32 - 26.5 ) ( specific heat of water is 1 cals / gm )
= 660
Heat lost = heat gained
4588S = 660
S = .14 cal /gm .
Specific heat of metal = .14 cal / gm
Answer:
350 J
Explanation:
The law of conservation of energy states that energy can neither be created nor destroyed but can only be converted from one form to another. This means that in a system, energy is not lost.
In this question, an unlit match contains approximately 1,000 J of chemical energy. When lit, thermal and light energy are emitted i.e. it gets converted to light and heat energy. If the thermal energy emitted was measured to be 400J, and the remaining match still contains 250J of chemical energy, then:
The amount of light energy emitted will be:
Total chemical energy (1000J) - {Remaining chemical energy (250J) + emitted thermal energy (400J)}
= 1000 - (400 + 250)
= 1000 - 650
= 350
Hence, the amount of light energy emitted is 350J
Note that, the amount of energy converted (thermal and light) and remaining chemical energy still equates the total chemical energy in the match.
Answer:
Explanation:
Given
Distance = 1 mile
Time = 8.92 minutes
Required
Calculate Speed in km/hr
Speed is calculated as thus;
Substitute 1 mile for distance and 8.92 minutes for time
Convert Miles to Kilometres
If
;
Then
--- (1)
Convert minutes to hour
Multiply both sides by 8.92
---- (2)
By substituting (1) and (2) in , we have
-- Approximated
