Why is pure oxygen stored as a liquid under pressure?

A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain

seraphim [82]

Answer:

161 atoms

Explanation:

A sample of propane, C3H8, contains 14.6 moles of carbon atoms. How many total moles of atoms does the sample contain

every molecule of propane contains 3+8=11 atoms

so

14.6 moles contain 14.6 X 11 = 161 atoms

4 0

3 years ago

how many liters of O2 are needed to produce 5.62 g of SO2 in the following reaction? 4FeS2+11O2 ->2Fe2O3+8SO2

Liula [17]

8moles of SO_2 need 11mol O_2

1mol need=11/8=1.4molO_2

Moles of sO_2

$\\ \rm\hookrightarrow \dfrac{5.62}{64}=0.1$

So

Moles of O_2

1.4(0.1)=0.14mol

We know

1mol at STP=22.4L
1.4mol=0.14(22.4)=3.13L O_2

5 0

3 years ago

How can you recognize an alcohol?

gavmur [86]

Answer:

O D. It has an -OH group attached to the end of the molecule.

Explanation:

Some alcohols have hydroxyl group (OH) attached to the end of a molecule and some have it attached as a branch on the molecule

${ \rm{R - OH \: : \: primary \: alcohol \: (1 \degree)}} \\ \\ { \rm{R -(OH) - R {}^{i} \: : secondary \: alcohol \: (2 \degree)}} \\ \\ { \rm{R - R {}^{i} (OH) - R {}^{ii} \: : tertiary \: alcohol \: (3 \degree)}}$

R is aryl or alkyl group
OH is hydroxyl group

5 0

3 years ago

Which electron configuration represents a selenium atom in an excited state

chubhunter [2.5K]

2-7-18-7 because selenium atom would have a total of <span>a total of 34 electrons. Hope this helps!!</span>

7 0

3 years ago

Which of the following is an oxidation-reduction reaction? a. HCl(aq) + LiOH(aq) → LiCl(aq) + H2O(l) b. Pb(C2H3O2)2(aq) + 2 NaCl

saw5 [17]

Answer: Option (d) is the correct answer.

Explanation:

A reaction in which there occurs change in oxidation state of reacting species is known as an oxidation-reduction reaction.

(a) $HCl(aq) + LiOH(aq) \rightarrow LiCl(aq) + H_{2}O(l)$

Will be written as:

$H^{+} + Cl^{-} + Li^{+} + OH^{-} \rightarrow Li^{+} + Cl^{-} + H^{+} + OH^{-}$

In this reaction, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(b) $Pb(C_{2}H_{3}O_{2})_{2}(aq) + 2NaCl(aq) \rightarrow PbCl_{2}(s) + 2 NaC_{2}H_{3}O_{2}(aq)$

Will be written as:

$Pb^{2+} + 2C_{2}H_{3}OO^{-} + 2Na^{+} + 2Cl^{-} \rightarrow Pb^{2+} + 2Cl^{-} + 2Na^{+} + 2C2H3OO^{-}$

Similarly here, there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(c) $NaI(aq) + AgNO_{3}(aq) \rightarrow AgI(s) + NaNO_{3}(aq)$

Will be written as:

$Na^{+} + I^{-} + Ag^{2+} + NO^{2-}_{3} \rightarrow AgI(s) + Na^{+} + NO^{2-}_{3}(aq)$

Here, also there occurs no change in oxidation state of reacting species. Hence, it is not an oxidation-reduction reaction.

(d) $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$

So, here there occurs change in oxidation state of Mg from 0 to +2 and oxidation state of H changes from +1 to 0. Hence, it is an oxidation-reduction reaction.

Thus, we can conclude that $Mg(s) + 2 HCl(aq) \rightarrow MgCl_{2}(aq) + H_{2}(g)$ is an oxidation-reduction reaction.

7 0

4 years ago