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Lorico [155]
3 years ago
8

Q4) The changes that occur in an experiment that are directly caused by the experimenter (you) are called ___________.

Chemistry
1 answer:
egoroff_w [7]3 years ago
4 0

Answer:

Independent Variables

Explanation:

These are changes that are made by the experimenter. They are factors that one is able to manipulate or control their values.

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One way to refine iron from iron ore is to heat the ore with hydrogen gas at high temperatures. Which change increases the amoun
tensa zangetsu [6.8K]

Answer: Adding Hydrogen Gas

Explanation:

The Reduction Reaction that occurs during the refinement of Iron Ore is as follows:

Fe_3O_4 + H_2  -> 3FeO + H_2O\\\\FeO + H_2   -> Fe + H_2O

Since Hydrogen Gas is a reactant in the equation with Iron ore , adding more hydrogen gas will shift the reaction toward the right side, increase the amount of  refined iron produced.

8 0
4 years ago
Read 2 more answers
etermine the molar concentration of magnesium ions in a solution formed by mixing 100.0 mL of 0.100 M MgCl, solution with 100.0
marysya [2.9K]

Answer:

Molar concentration of magnesium ions in the final solution is 0.2 M.

Explanation:

c=\frac{n}{V}

c = Concentration of the solution

n =   moles of the compound

V = volume of the solution in L

1) Molarity of MgCl_2 solution = 0.100 M

Volume of MgCl_2 solution = 100.0 mL = 0.1 L

Moles of MgCl_2 in 100 mL solution= n

0.100 M=\frac{n}{0.1L}

n=0.01 mol

MgCl_2(aq)\rightarrow Mg^{2+}(aq)+2Cl^-(aq)

1 mole of magnesium chloride gives 1 mol of magnesium ions and 2 moles of chloride ions.

Then 0.01 moles of magnesium chloride will give:

x=\frac{1}{1}\times 0.01 mol=0.01 mol magnesium ions.

2) Molarity of Mg_3(PO_4)_2 solution = 0.100 M

Volume of Mg_3(PO_4)_2 solution = 100.0 mL = 0.1 L

Moles of Mg_3(PO_4)_2 in 100 mL solution= n'

0.100 M=\frac{n'}{0.1L}

n'=0.01 mol

Mg_3(PO_4)_2(aq)\rightarrow 3Mg^{2+}(aq)+2PO_{4}^-(aq)

1 mole of magnesium phosphate gives 3 mol of magnesium ions and 2 moles of phosphate ions.

Then 0.01 moles of magnesium phosphate will give:

y=\frac{3}{1}\times 0.01 mol=0.03 mol magnesium ions.

After mixing both solutions:

Moles of magnesium ions = x + y = 0.01 mol + 0.03 mol = 0.04 mol

Total volume after mixing = 0.1 L + 0.1 L = 0.2 L

Molar concentration of magnesium ions in the final solution:[Mg^{2+}]

[Mg^{2+}]=\frac{0.04 mol}{0.2 L}=0.2 mol/L

4 0
4 years ago
How many oxygen atoms are in<br> Ba(MnO4)2?
vlabodo [156]

Answer:

4

Explanation:

5 0
2 years ago
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A student needs 500 mL of a 1.5 M solution of NaCl for an experiment. How many moles of NaCl should she use?
masha68 [24]

Answer:

She should use 0.75 mol.

Explanation:

By definition, molarity (M) is the <u>number of moles of solute per liter of solution</u>. One liter of solution is equal to 1000 mL.

Therefore,

1000 mL -------- 1.5 moles of NaCl

500 mL --------- x= 0.75 moles of NaCl

The moles contained in 500 mL of a 1.5 M NaCl solution are 0.75.

5 0
3 years ago
What does a salt bridge do?
Andrew [12]

Answer:

A salt bridge or ion bridge, in electrochemistry, is a laboratory device used to connect the oxidation and reduction half-cells of a galvanic cell (voltaic cell), a type of electrochemical cell. It maintains electrical neutrality within the internal circuit.

Explanation:

5 0
3 years ago
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