Cold someone help with this plz
1 answer:
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Answer:
The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.
Step-by-step explanation:
Here, according to the question:
Total number of yellow highlighters = 12
Total number of blue highlighters = 6
Total number of green highlighters = 4
Total number of orange highlighters = 3
So, the total number of highlighters = 12 + 6 + 4 + 3 = 25
Let E1 : Event of selecting a yellow highlighter.
P(E1) = =
Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.
So, the total yellow highlighters left after selecting one = 12 -1 = 11
Also, the number of blue highlighter = 6
So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17
P(E2) =
=
Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.
Answer:
b. (1, 13).
Step-by-step explanation:
Here's a pic of my work. You can put either equation on the other side of the equal sign, because they both equal Y. therefore, they equal each other.
