Answer:
Hi! I hope this is correct please inform me if this is incorrect :)
a = 1 will have.
2a + 3 < 9 - 3a.
2a + 3 > 10 -3a.
3a - 2a + 1>2.
a = 2 will have
ANY others I did not include in a = 1 :)
Please once again tell me if this is incorrect.
Step-by-step explanation:
Answer:
86
Step-by-step explanation:
Answer:
b. about 63.9 units and 41.0 units
Step-by-step explanation:
In question ∠a= 29° and Side of a= 15 and b= 20
Using sine rule of congruence of triangle.
⇒ 
⇒ 
Using value of sin 29°
⇒ 
Cross multiplying both side.
⇒ Sin B= 
∴ B= 41°
Now, we have the degree for ∠B= 41°.
Next, lets find the ∠C
∵ we know the sum total of angle of triangle is 180°
∴∠A+∠B+∠C= 180°
⇒ 
subtracting both side by 70°
∴∠C= 110°
Now, again using the sine rule to find the side of c.

⇒
Using the value of sine and cross multiplying both side.
⇒ C= 
∴ Side C= 28.92.
Now, finding perimeter of angle of triangle
Perimeter of triangle= a+b+c
Perimeter of triangle= 
∴ Perimeter of triangle= 63.9 units
The valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
<h3>How to determine the valid exclusion?</h3>
The expression is given as:
8ab^2x/4a^2b - 8ab^2
Set the denominator to 0
4a^2b - 8ab^2 = 0
Divide through by 4ab
a - 2b = 0
Add 2b to both sides
a = 2b
Hence, the valid exclusion of the algebraic fraction is (c) a =0, b =0, a =2b
Read more about algebraic fraction at:
brainly.com/question/4344214
#SPJ1
Answer:

Step-by-step explanation:
V = length × width × height
SO...
V = 1ft × 1ft × 2ft
V = 