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ryzh [129]
3 years ago
8

two pipes together can fill a tank in 12 hours alone the smaller pipe can take 7 hours longer than the larger pipe takes to fill

the tank how long does it take the smaller pipe alone to fill the tank
Mathematics
1 answer:
Rashid [163]3 years ago
3 0

Well you should just have to add 7 to 12.

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7.1 + 7= 14.1
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How do you find out the percentage of 55% of 140
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I just found 10% of it, which is 14, then found 5% of it through the previous work, which is 7

then i multiplied 7 by 11, because 55/5 is 11, so 55% of 140 is 77
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A bag contains 5 red marbles 7 yellow marbles and 3 blue marbles what is the probability of not drawing one blue marble at rando
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Answer:

You have a 0.8 / 80% of NOT picking the blue marbles.

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A distribution of values is normal with a mean of 60 and a standard deviation of 16. From this distribution, you are drawing sam
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Answer:

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

A distribution of values is normal with a mean of 60 and a standard deviation of 16.

This means that \mu = 60, \sigma = 16

Samples of size 25:

This means that n = 25, s = \frac{16}{\sqrt{25}} = 3.2

Find the interval containing the middle-most 76% of sample means.

Between the 50 - (76/2) = 12th percentile and the 50 + (76/2) = 88th percentile.

12th percentile:

X when Z has a p-value of 0.12, so X when Z = -1.175.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.175 = \frac{X - 60}{3.2}

X - 60 = -1.175*3.2

X = 56.24

88th percentile:

Z = \frac{X - \mu}{s}

1.175 = \frac{X - 60}{3.2}

X - 60 = 1.175*3.2

X = 63.76

The interval containing the middle-most 76% of sample means is between 56.24 and 63.76.

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You can avoid algebra & simply calculate the expression's value with each of the answers
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