-1(2x+3)-2(x-1)
-2x-3-2x+2
-4x-1
Yes. As long as it is linear, it will be continuous no matter the numbers. Now, I have no idea what a "real" number is, but I hope this helped.
Answer:
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Answer:
Option B) -9 is correct
The evaluated given expression when x=-3 is 2x+x=-9
Step-by-step explanation:
Given expression is 2x+x
Now to evalute the given expression when x=-3 as below :
2x+x when x=-3
That is put x=-3 in the given expression we get
2x+x=2(-3)+(-3)
=-6-3
=-9 ( adding the like terms here )
Therefore 2x+x=-9
The evaluated given expression when x=-3 is 2x+x=-9
Option B) -9 is correct
<h3><u>d^3 - 4bd^2 + 16b^2d - 64d^3 is the expanded binomial.</u></h3>
The binomial theorem involves Pascal's triangle, and essentially gives you the coefficients for the formula you're going to use to expand it.
In this case, the coefficients will be 1, 3, 3, and 1.
We can set up our formula like this:
(a + (-b)) = a^3 + a^2b + ab^2 + b^3
Now we can just plug in our values:
(d + (-4b))^3 = d^3 + d^2(-4b) + d(-4b)^2 + (-4b)^3
Now, we can simplify the equation.
(d + (-4b))^3 = d^3 - 4bd^2 + 16b^2d - 64d^3
