4350? I'm not sure what you meant. All of those numbers are above 0.47. If you meant 0.750, 0.1950, 0.2150, or 0.4350, then it's 0.4350
Answer:
Step-by-step explanation:
Given Ben's observations when the wait time is as advertised represented by the equation 2|x − 2| − 12 = 0, to get the times when the serving time is as advertised, relative to noon, we will calculate for the value of x in the equation;
Note that the modulus of the function |x-2| will return both positive and negative value.
For the positive value of |x-2|;
2|x − 2| − 12 = 0
2(x − 2) − 12 = 0
open the parenthesis
2x-4 - 12 = 0
2x - 16 = 0
add 16 to both sides
2x-16+16 = 0+16
2x = 16
x = 16/2
x = 8
For the negative value of |x-2|;
2|x − 2| − 12 = 0
-2(x − 2) − 12 = 0
open the parenthesis
-2x+4 - 12 = 0
-2x - 8 = 0
add 8 to both sides
-2x-8+8 = 0+8
-2x = 8
x = -8/2
x = -4
<em>Hence the times when the serving time is as advertised, relative to noon are 8minutes and 4minutes </em>
Answer:
<em>x = 3 and y = 0</em>
Step-by-step explanation:
3y+x=3
-2y+5x=15
Isolate y in 3y + x = 3 :
Substitute 
in -2y + 5x = 15 :
Simplify the equation :
Isolate x in 
:
Proving x = 3
Isolate y in 
:
Proving y = 0
Your solved system of equations are x being 3, and y being 0.
Answer:
the answer is D
Step-by-step explanation:
on edge2020
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