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mariarad [96]
3 years ago
14

What type of bond is formed when two or more water molecules interact?

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

hydrogen bond

Explanation:

Water has atom of oxygen and 2 atoms of hydrogen. The bond is formed between oxygen of one molecule and hydrogen of another molecule. This bond is called hydrogen bond.

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A 3 N force pushing to the right on a box causes it to accelerate 6 m/s² to the right. What is the mass of the box?
Aloiza [94]

18 kg would be the answer to that


8 0
3 years ago
A proton accelerates from rest in a uniform electric field of 680 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativis
Ksivusya [100]

Answer:

Acceleration, a=6.51\times 10^{10}\ m/s^2                                                

Explanation:

Given that,

Electric field, E = 680 N/C

Speed of the proton, v = 1.3 Mm/s

We need to find the acceleration of the proton. We know that the force due to motion is balanced by the electric force as :

qE=ma

a and m are the acceleration and mass of the proton.

a=\dfrac{qE}{m}

a=\dfrac{1.6\times 10^{-19}\times 680}{1.67\times 10^{-27}}

a=6.51\times 10^{10}\ m/s^2

So, the acceleration of the proton is a=6.51\times 10^{10}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
Once again we have a skier on an inclined plane. The skier has mass M and starts from rest. Her speed at the bottom of the slope
mars1129 [50]

Answer:

v = 31.3 m / s

Explanation:

The law of the conservation of stable energy that if there are no frictional forces mechanical energy is conserved throughout the point.

Let's look for mechanical energy at two points, the highest where the body is at rest and the lowest where at the bottom of the plane

Highest point

       Em₀ = U = m g y

Lowest point

     Em_{f} = K = ½ m v²

As there is no friction, mechanical energy is conserved

       Em₀ = Em_{f}

       m g y = ½ m v²

       v = √ 2 g y

Where we can use trigonometry to find and

       sin 30 = y / L

       y = L sin 30

Let's replace

      v = RA (2 g L sin 30)

Let's calculate

      v = RA (2 9.8 100.0 sin30)

      v = 31.3 m / s

4 0
2 years ago
The term ampacity is defined as the _____ current, in amperes, that a conductor can carry continuously under conditions of use w
White raven [17]

Answer:

The maximum current, in amperes, that a conductor can carry continuously under the conditions of abuse without exceeding its temperature rating.

5 0
3 years ago
A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 6.0 oz. Aluminum has a density of 2.70 g/cm3. Wh
SIZIF [17.4K]

Answer:

1.36 x 10^-3 cm

Explanation:

Area = 50 ft^2 = 46451.5 cm^2

mass = 6 oz = 170.097 g

density = 2.70 g/cm^3

Let t be the thickness of foil in cm.

mass = volume x density

mass = area x thickness x density

170.097 = 46451.5 x t x 2.70

t = 1.36 x 10^-3 cm

Thus, the thickness of aluminium foil is 1.36 x 10^-3 cm.

3 0
2 years ago
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