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4 years ago

What type of bond is formed when two or more water molecules interact?

Physics

1 answer:

lara31 [8.8K]4 years ago

4 0

Answer:

hydrogen bond

Explanation:

Water has atom of oxygen and 2 atoms of hydrogen. The bond is formed between oxygen of one molecule and hydrogen of another molecule. This bond is called hydrogen bond.

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Which of the following brain imaging techniques produce the most detailed picture of brain structure? (2 points)

Inga [223]

Answer:

MRI

Explanation:

Magnetic Resonance Imaging, furnishes the most detailed picture of brain structure. MRI produces the most point by point picture of the cerebrum. MRI examines by using attractive fields and radio waves to create PC produced pictures that recognize the structures inside the mind. It gives the most point by point and a detailed image of the brain structure.

6 0

3 years ago

The spaceship Intergalactic landed on the surface of the uninhabited Pink Planet, which orbits a rather average star in the dist

max2010maxim [7]

Answer:

Explanation:

Given

Length of the pendulum L = 1.44 m

Number of complete cycles of oscillation n = 1.10 x 10^2

total time of oscillation t = 2.00 x 10^2 s

The period of the T = n/t

T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s

The period of a pendulum is gotten as

T = $2\pi \sqrt{\frac{L}{g} }$

where g is the acceleration due to gravity

substituting values, we have

0.55 = $2\pi \sqrt{\frac{1.44}{g} }$

0.0875 = $\sqrt{\frac{1.44}{g} }$

squaring both sides of the equation, we have

7.656 x 10^-3 = 144/g

g = 144/(7.656 x 10^-3) = <em>18808.7 m/s^2</em>

3 0

3 years ago

If a ball is thrown vertically upward from the roof of 32 foot building with a velocity of 64 ft/sec, its height after t seconds

stepan [7]

Answer:

a) $s_{max} = 96\,ft$ , b) $v(4.449\,s) = -78.368\,\frac{ft}{s}$

Explanation:

a) The maximum height is obtained with the help of the First and Second Derivative Tests:

First Derivative

$v(t) = 64 - 32\cdot t$

$64 - 32\cdot t = 0$

$t = 2\,s$

Second Derivative

$a(t) = -32$ (absolute maximum)

The maximum height reached by the ball is:

$s (2\,s) = 32 + 64\cdot (2\,s) - 16\cdot (2\,s)^{2}$

$s_{max} = 96\,ft$

b) The time required by the ball to hit the ground is:

$32+64\cdot t - 16\cdot t^{2} = 0$

$-16\cdot (t^{2}-4\cdot t - 2) = 0$

$t^{2}-4\cdot t - 2 = 0$

$(t -4.449)\cdot (t+0.449)\approx 0$

Just one root offers a solution that is physically reasonable:

$t = 4.449\,s$

The velocity of the ball when it hits the ground is:

$v(4.449\,s) = 64 - 32\cdot (4.449\,s)$

$v(4.449\,s) = -78.368\,\frac{ft}{s}$

6 0

3 years ago

Read 2 more answers

A block (6 kg) initially compresses spring #1 (k = 2000 N/m) by 60 cm from its equilibrium point. When the block is released, it

mart [117]

Answer:

block K = 29.39 J and spring #1 Ke = 360 J

Explanation:

In this problem we have that the elastic energy of the spring becomes part kinetic energy and the part in work against the force of friction, so, to use the law of conservation of energy, the decrease in energy is the rubbing force work

$W_{fr}$ = Ef - E₀

Let's look for the energies

Initial

E₀ = Ke = ½ k₁ x₁²

Final, this is just before starting to compress the spring

Ef = Ke = ½ m v²

The work of the rubbing force is

$W_{fr}$ = -fr x

Let's write Newton's second law the y axis

N-W = 0

N = W

fr = μ N

fr = μ mg

Let's replace

-μ mg x = ½ m v² - ½ k₁ x₁²

v² = 2/m (½ k₁ x1₁² -μ mg x)

v² = 2/6 (½ 2000 0.6²2 - 0.5 6 9.8 1) = 1/3 (360 - 29.4)

v = 3.13 m / s

With this value we calculate the energy of the block

K = ½ m v²

K = ½ 6 3.13²

K = 29.39 J

Calculate eenrgy of the spring ke 1

Ke = ½ k₁ x₁²

Ke = ½ 2000 0.60²

Ke = 360 J

4 0

3 years ago

Im Giving 50 Points!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

nlexa [21]

B.f. skinner is the founder of operant conditioning .

4 0

3 years ago

Read 2 more answers