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victus00 [196]
3 years ago
8

Where would the barycenter of these two bodies be located given their masses?

Physics
1 answer:
n200080 [17]3 years ago
3 0

It's kinda tough, since we don't know the actual numerical locations of the points, only an approximate picture.

The big ball has 11 times the mass of the small ball, so the small ball is 11 times as far from the barycenter as the big ball is.

If any of the points is marked at the actual barycenter, it can only be point-A .

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Plane polarized light with intensity I0 is incident on a polarizer. What angle should the principle axis make with respenct to t
Nataliya [291]

Answer:

 Q = 47.06 degrees

Explanation:

Given:

- The transmitted intensity I = 0.464 I_o

- Incident Intensity I = I_o

Find:

What angle should the principle axis make with respect to the incident polarization

Solution:

- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:

                                     I = I_o * cos^2 (Q)

- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:

                                     Q = cos ^-1 (sqrt (I / I_o))

- Plug the values in:

                                     Q = cos^-1 ( sqrt (0.464))

                                     Q = cos^-1 (0.6811754546)

                                     Q = 47.06 degrees

                                   

8 0
3 years ago
A suspended object A is attracted to a charged object B, can one conclude that A is charged? Explain
irinina [24]

Explanation:

In my view, when the Object A is attracted to a Charged object B. Object B should be Negatively or Positively charged. So Object B should be the Opposite charged according to the Object B

Example =

If Object B is Negatively Charged, the Object A should be Positively Charged

If the Object B is Positively Charged, the Object A should be Negatively Charged

Sometimes it can Mix as a Neutral as well

Hope this Helps

5 0
3 years ago
A 330.-ohm resistor is connected to a 5.00-volt battery. What is the current through the resistor?
Gelneren [198K]

I = 0.0152 A = 15.2 mA

Explanation:

Using Ohm's law,

V = IR or

I = V/R

= (5.00 V)/(330. ohms)

= 0.0152 A

= 15.2 mA

8 0
3 years ago
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The inventor of the electric cell was:<br> O Coulomb<br> Franklin<br> o Gilbert<br> O Volta
Tomtit [17]

Answer:

The inventor of the electric cell was:

Alessandro Volta (in other words, Volta)

Explanation:

3 0
3 years ago
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What is described by the terms body-centered cubic and face-centered cubic?
Montano1993 [528]
In physical chemistry, the terms body-centered cubic  (BCC) and face-centered cubic (FCC) refer to the cubic crystal system of a solid. Each solid is made up simple building blocks called lattice units. There are different layouts of a lattice unit.

It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.

7 0
3 years ago
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