Answer:
given,
mass of copper = 100 g
latent heat of liquid (He) = 2700 J/l
a) change in energy
Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (300 - 4)
Q = 11153.63 J
He required
Q = m L
11153.63 = m × 2700
m = 4.13 kg
b) Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (78 - 4)
Q = 2788.41 J
He required
Q = m L
2788.41 = m × 2700
m = 1.033 kg
c) Q = m Cp (T₂ - T₁)
Q = 0.1 × 376.812 × (20 - 4)
Q = 602.90 J
He required
Q = m L
602.9 = m × 2700
m =0.23 kg
The student must have made an error in her measurement in the concentration of hydrogen ion in the basic solution given. From her measurement, the concentration is 1 × 10−3 M. If we calculate the pH, we get:
pH = -log ( 1 × 10−3) = 3
A pH of 3 does not signifies a basic solution it is in the acidic range. So, the measurement is wrong.
Answer:
Where the electric potential is constant, the strength of the electric field is zero.
Explanation:
As a test charge moves in a given direction, the rate of change of the electric potential of the charge gives the potential gradient whose negative value is the same as the value of the electric field. In other words, the negative of the slope or gradient of electric potential (V) in a direction, say x, gives the electric field (Eₓ) in that direction. i.e
Eₓ = - dV / dx ----------(i)
From equation (i) above, if electric potential (V) is constant, then the differential (which is the electric field) gives zero.
<em>Therefore, a constant electric potential means that electric field is zero.</em>
Answer:
Honestamente yo no se cual es la pregunta que escribiste
Answer:
-There are no other charges nearby.
Explanation:
-There are no other charges nearby.
If there is no net charge in nearby space then the force on this charge will be ZERO
-If there are other charges nearby, they must all have the same sign as Q.
There there is nearby charge of same sign then it will have repulsion force on Q
-If there are other charges nearby, they must all have the opposite sign of Q.
if there is nearby charge of opposite sign then the force must be attraction force.
-If there are other charges nearby, the total positive charge must equal the total negative charge.
If there exist two type of charges nearby then there may exist either attraction or repulsion force on it
