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lozanna [386]
3 years ago
12

Find the solution to the equation x^2-7x=0

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer:

x₁ = 0

x₂ = 7

Step-by-step explanation:

x² - 7x = 0

x(x - 7) = 0

x₁ = 0

x - 7 = 0 => x₂ = 7

lara [203]3 years ago
5 0

Answer:

x = 0   <u><em> OR </em></u>   x = 7

Step-by-step explanation:

=> x^2-7x=0

Taking x common

=> x(x-7) = 0

<u><em>Either,</em></u>

x = 0   <u><em>OR </em></u>   x-7 = 0

x = 0   <u><em> OR </em></u>   x = 7

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Answer:

27/4 or 6 3/4

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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6 0
4 years ago
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6 0
3 years ago
For the solid described below, find the dimensions giving the minimum surface area, given that the volume is 64 cm3. a closed cy
stepladder [879]
The volume of the cylinder is:
 V = pi * r ^ 2 * h = 64
 The surface area is:
 A = 2 * pi * r ^ 2 + 2 * pi * r * h
 We write the area as a function of r:
 A (r) = 2 * pi * r ^ 2 + 2 * pi * r * (64 / (pi * r ^ 2))
 Rewriting:
 A (r) = 2 * pi * r ^ 2 + 2 * (64 / r)
 A (r) = 2 * pi * r ^ 2 + 128 / r
 Deriving:
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 128 / r ^ 2 = 4 * pi * r
 r ^ 3 = 128 / (4 * pi)
 r = (128 / (4 * pi)) ^ (1/3)
 r = 2.17 cm
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 Answer:
 
The dimensions giving the minimum surface area are:
 
r = 2.17 cm
 
h = 4.33 cm
8 0
3 years ago
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