Question

PLZ, HELP WORTH 30 PTS!!!! WILL MARK BRANLIEST!!!

Answer 1

Answer:

Therefore the equation of the required line is y = $\frac{-1}{2}$x + 2 or 2y + x = 4.

Step-by-step explanation:

i) when x = -2 then y = 3 so the line from x = -2 to x = 2 has the point (-2, 3)

ii)when x = 2 then y = 1 so the line from x = -2 to x = 2 has the point (2, 1)

iii) if two points in a line are given then slope of equation passing through the lines is given by

slope m = $\frac{y_{2} - y_{1} }{x_{2} - x_{1} }$ = $\frac{1 - 3}{2 - (-2)}$ = $\frac{-2}{4}$  =  $\frac{-1}{2}$

So from the general equation of a line y = mx + c

we get y = $\frac{-1}{2}$x + c and substituting for x and y with (-2, 3) respectively we get

3 = 1 + c. Therefore c = 2.

Therefore the equation of the required line is y = $\frac{-1}{2}$x + 2 or 2y + x = 4.