Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
Y=17400(1+0.025)^8 is your equation and with that you get $21200.21
Answer:
You would figure this out by the method of substitution
Step-by-step explanation:
a= -3/2
b= 5/4
c=7/8
a(b+c) = a(b)+a(c)
Substitute
-3/2(5/4 +7/8) = -3/2(5/4)+-3/2(7/8)
-51/16 =-51/16
I believe you go to the spots on the graph and then just found up from there, and do that with every point
Find the difference between each term, (e.g 3,5,7,9 —> the difference is 2 so it would be 2n) and then you minus that number from the first term (3-2=1) so therefore the nth term for that sequence would be 2n + 1
