Answer:
747
Step-by-step explanation:
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Answer:
1.) 48
2.) 65
3.) 36
Step-by-step explanation:
1.) If the equation is 6(x-4) and x = 12, then all we have to do is plug in the value of x. When we plug in, all we do is substitute 12 for x because they mentioned in the question that x = 12. So, we end up getting 6(12 - 4). After solving this, we get 48.
2.) This problem is a lot like the last problem. All we need to do is substitute /plug in the values of x and y into the equation, to get 4(4^2) - 35/7 - (8 + 14). After solving, we get 65.
3.) . This problem, once again, is also a lot like the last problems. We need to substitute the value of x into the equation 8x+12. Since we know from the problem that x is 3, all we have to do is 8 * 3 + 12.
Put it in the form
ax^2 + bx + c = 0
use the quadratic formula
x = [ -b + sqrt( b^2 - 4 ac ) ] / 2a
x = [ -b - sqrt( b^2 - 4 ac ) ] / 2a
7v^2 - 7v - 22 = 0
a = 7
b = -7
c = -22
v = [ 7 + sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = 2.34
v = [ 7 - sqrt ( 49 - 4 * 7 ( -22) ] / 2 * 7 = -1.34