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3 years ago

Choose the equation of the vertical line passing through the point (-4, 2). i picked x = -4.. ...?

Mathematics

1 answer:

Sliva [168]3 years ago

3 0

Yes that is right
x=-4 is a vertical line passing through the points (-4,y)
where y can be any value

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In May Mr. Lee's earings were 60 percent of the Lee family's total income. In June Mr. Lee earned 20 percent more than in May. I

murzikaleks [220]

Answer: 64.29%

Step-by-step explanation:

Let the total earnings of the Lee family in May be x

Amount earned by Mr Lee in May = 60% of x = 0.6x

Amount earned by other family members in May = x - 0.6x (total earnings - Mr Lee's earnings) = 0.4x

Amount earned by Mr Lee in June = 20% more than what Mr Lee earned in May.

That is, amount earned by Mr Lee in June = 1.2 × 0.6x = 0.72x

Amount earned by other members of the family in June remains unchanged, that is = 0.4x

Total amount earned by the Lee family in June = 0.72x + 0.4x = 1.12x

Percentage of total earnings in June earned by Mr. Lee = (0.72x/1.12x) × 100% = 64.29%.

QED!

6 0

3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f +9)(x).

Valentin [98]

Answer:

4x +1

Step-by-step explanation:

f(x) = 3x - 1

g(x) = x + 2,

(f +g)(x)= 3x-1 + x+2

Combine like terms

=4x +1

8 0

3 years ago

Read 2 more answers

What is the equation of this graphed line?

Soloha48 [4]

Y=2x+2
.......................

7 0

3 years ago

PLEASE HELP DUE TODAY

Brut [27]

Answer:

It is 7 devided by 11

0.6363636363

Step-by-step explanation:

5 0

3 years ago

The graph of which function has a minimum located at (4, –3)?

valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^{2}+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ <u>but is not a minimum</u>

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^{2}-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

$f(x)=(x-2)^{2}+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^{2}-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

$f(x)-3=2(x^{2}-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

7 0

3 years ago

Read 2 more answers