Let the number of red, black, green and blue balls be R, B, G, U respectively.
B=R (There are as many black balls as red balls)
G+R=10 so G=10-R (Green balls and red balls should add up to 10)
R+10=U (There should be 10 more blue balls than red balls)
The minimal number of balls is 2, 304 so we have the following inequality:
R+B+G+U≥ 2,304
R+(R)+(10-R)+ (R+10)≥2,304
4R≥2,304
R≥2,304/4=576 so R=576
Answer: 576
Answer:
7m^4-52m^3-28m^2+67m+42
Step-by-step explanation:
(7m^2-3m-7)(m^2-7m-6)
7m^4-3m^3-7m^2-49m^3+21m^2+49m-42m^2+18m+42
7m^4-3m^3-49m^3-7m^2+21m^2-42m^2+49m+18m+42
7m^4-52m^3-28m^2+67m+42
Answer:
b. x = 11/8, x = 59/72.
Step-by-step explanation:
4|8x - 6| = 5|-8x + 7|
square both sides:
16(64x^2 - 96x + 36) = 25( 64x^2 - 112x + 49)
1600x^2 - 1024x^2 - 2800x + 1536x + 1225 - 576 = 0
576x^2 - 1264x + 649 = 0
x = [1264 +/- √(1264^2 - 4 * 576* 649)] / (2*576)
x = 11/8, x = 59/72.
Answer:
John I did my phone in a while and my mom did it I was so
Step-by-step explanation: