Answer:
Two possible lengths for the legs A and B are:
B = 1cm
A = 14.97cm
Or:
B = 9cm
A = 12cm
Step-by-step explanation:
For a triangle rectangle, Pythagorean's theorem says that the sum of the squares of the cathetus is equal to the hypotenuse squared.
Then if the two legs of the triangle are A and B, and the hypotenuse is H, we have:
A^2 + B^2 = H^2
If we know that H = 15cm, then:
A^2 + B^2 = (15cm)^2
Now, let's isolate one of the legs:
A = √( (15cm)^2 - B^2)
Now we can just input different values of B there, and then solve the value for the other leg.
Then if we have:
B = 1cm
A = √( (15cm)^2 - (1cm)^2) = 14.97
Then we could have:
B = 1cm
A = 14.97cm
Now let's try with another value of B:
if B = 9cm, then:
A = √( (15cm)^2 - (9cm)^2) = 12 cm
Then we could have:
B = 9cm
A = 12cm
So we just found two possible lengths for the two legs of the triangle.
Answer:
9 boxes were packed. 10 brownies were left over.
Step-by-step explanation:
127 ÷ 13 = 9 R10
13 x 9 = 10 x 9 + 3 x 9 = 90 + 27 = 117
127 - 117 = 10
Hi Dezariaspencer
All we have to do is simply add 2x to both sides and we have our answer.
Answer: y = 11 + 2x.
Thank you for asking your question, have a good day.
Answer:
yes
Step-by-step explanation: