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timurjin [86]
3 years ago
7

You are driving your 1,000kg car at 20m/s. After seeing a red light, you press the brakes and come to rest. Your brakes use fric

tion to slow you down, so thermal energy is created. How much was created bringing you to a stop?
Physics
1 answer:
Drupady [299]3 years ago
6 0
50kg 
1000/20= 50
i beliebe thats the answer. hoped i helped
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1) Little Timmy wants to measure how tall his house is. He doesn’t have a tape measure but does have a stopwatch. He recruits Bi
kifflom [539]

1) 13.7 m

The motion of the rock is a free fall, with constant acceleration g=9.8 m/s^2 towards the ground, so the total distance it covers is given by the SUVAT equation:

S=\frac{1}{2}gt^2

where S is the height of the house, and t is the time the rock takes to reach the ground. Substituting t=1.67 s, we find:

S=\frac{1}{2}(9.8 m/s^2)(1.67 s)^2=13.7 m

2) 105.5 m

The motion of the stuffed chicken is a projectile motion, with a uniform horizontal motion (with constant velocity of v=36.0 m/s) and a vertical accelerated motion (with constant acceleration of g=9.8 m/s^2).

First of all, we can find the total time of the ball by considering the vertical motion only. We know the vertical distance covered, S=42.2 m, so the time of the fall is

S=\frac{1}{2}gt^2\\t=\sqrt{\frac{2S}{g}}=\sqrt{\frac{2(42.2 m)}{9.8 m/s^2}}=2.93 s

And now we can consider the horizontal motion to find the horizontal distance covered by the stuffed chicken:

d=vt=(36.0 m/s)(2.93 s)=105.5 m

3) 49.4 m

Again, the motion of the ball is a projectile motion, with a horizontal motion and a vertical motion.

The range of a projectile launched from the ground can be found by using the formula:

d=\frac{v^2}{g} sin 2 \theta

where, in this case:

v = 22.0 m/s is the initial velocity

\theta=45^{\circ}

Substituting into the formula, we find

d=\frac{(22.0 m/s)^2}{9.8 m/s^2}(sin (2\cdot 45^{\circ}))=49.4 m

4) 9.6 m/s^2

The frictional force acting on the monkey is given by:

F_f = \mu mg=(0.16)(31.0 kg)(9.8 m/s^2)=48.6 N

where \mu is the coefficient of friction and m is the mass of the monkey.

We have two forces acting on the monkey: the push of F=345 N and the frictional force acting in the opposite direction. According to Newton's second law, the net force will be equal to the product between the monkey's mass and its acceleration, so we can find the acceleration:

F-F_f=ma\\a=\frac{F-F_f}{m}=\frac{345 N-48.6 N}{31.0 kg}=9.6 m/s^2

5) 462.3 N

The horizontal component of the pushing force is:

F_x = F cos \theta = (648 N)(cos 25^{\circ})=587.3 N

The frictional force, acting in the opposite direction, is

F_f = \mu mg=(0.17)(75.0 kg)(9.8 m/s^2)=125.0 N

where \mu is the coefficient of friction and m is the mass of the box.

The net force on the box is therefore given by the net force on the horizontal direction:

F_{net}=F_x -F_f=587.3 N -125.0 N=462.3 N

6) 89.5 N

First of all we need to calculate the total weight of the table and the items above it.

The weight of the table is:

W=mg=(25.0 kg)(9.8 m/s^2)=245 N

So the total weight of the table and the items is

W=245 N+63 N+12 N+44 N+24 N+9N+10N=407 N

The force needed to get the table moving must be at least equal to the frictional force, which is equal to the product between the coefficient of friction and the weight of the all stuff:

F=F_f = \mu W=(0.22)(407 N)=89.5 N

7 0
3 years ago
A 10.0-g bullet is fired into a 200-g block of wood at rest on a horizontal surface. after impact, the block slides 8.00 m befor
miss Akunina [59]
<span>Step 1 -- determine the acceleration of the 200-g block after bullet hits it a = (coeff of friction) * g g = acceleration due to gravity = 9.8 m/sec^2 (constant) a = 0.400*9.8 a = 3.92 m/sec^2 Step 2 -- determine the speed of the block after the bullet hits it Vf^2 - Vb^2 = 2(a)(s) where Vf = final velocity = 0 (since it will stop) Vb = velocity of block after bullet hits it a = -3.92 m/sec^2 s = stopping distance = 8 m (given) Substituting values, 0 - Vb^2 = 2(-3.92)(8) Vb^2 = 62.72 Vb = 7.92 m/sec. M1V1 + M2V2 = (M1 + M2)Vb where M1 = mass of the bullet = 10 g (given) = 0.010 kg. V1 = velocity of bullet before impact M2 = mass of block = 200 g (given) = 0.2 kg. V2 = initial velocity of block = 0 Vb = 7.92 m/sec Substituting values, 0.010(V1) + 0.2(0) = (0.010 + 0.2)(7.92) Solving for V1, V1 = 166.32 m/sec. Therefore the answer is (B) 166 m/s!</span>
6 0
3 years ago
4) A force of 500 N acts on an area of 0.05m2. Find the pressure in Pascal.
snow_tiger [21]

Answer:

pressure = force ie 500 N divided by area ie 0.05m².

p=f by a

p= 500n divided by 0.05 m²

p= 10,000 pascal

6 0
3 years ago
An automobile slows from 26 m/s to 18 m/s. Its acceleration is −2.0 m/s 2 . How much time does it take for the vehicle to slow d
Serggg [28]

Answer:4.0s

Explanation:jus is

4 0
3 years ago
Please help on this one?
nikdorinn [45]

a is the right answer

4 0
3 years ago
Read 2 more answers
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