How much mass is needed for a black hole?

In which direction does earth's magnetic field move?

Natasha2012 [34]

Answer:

c

Explanation:

because the repelling force of gravity is vertical

4 0

3 years ago

Genes are organized on matching pairs of _______.

natta225 [31]

Answer:

homologous chromosomes

Explanation:

6 0

3 years ago

At what distance is the electrostatic force between two protons equal to the weight of one?.

erik [133]

0.118 m is the distance between the two protons.

Mass of proton = 1.6726 × 10⁻²⁷ kg

Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N

= 1.6408 × 10⁻²⁶ N

Charge of proton = 1.602 × 10⁻²⁹ C

The force between two protons = kq²/r² where, K is a proportionality

constant, q is a charge of proton and

r is the distance between two protons.

= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²

To calculate distance :

Weight of proton= Force between protons

⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²

⇒ r = 0.118m

Therefore, 0.118 m is the distance between the two protons.

Learn more about electrostatic force here:

brainly.com/question/18108470

#SPJ4

8 0

2 years ago

Consider the elementary gas-phase reversible reaction A 3C Pure A enters at a temperature of 400 K and a pressure of 10 atm. At

xxMikexx [17]

Answer:

39%

Explanation:

The equilibrium equation is:

$A\rightleftharpoons 3C$

The initial concentration of A can be calculated from the ideal gas equation:

$pV=nRT\\\\n/v=p/(RT)\\\\C_A=\dfrac{10atm}{0.08206(atm-dm^3/K-mol)/times 400K}\\\\C_A=0.304mol/liter$

Determine the conversion of substance A to substance C using an ICE table and the Kc constant:

A ⇄ 3C

I 0.304 0

C - x + 3x

E 0.304 - x 3x

$K_c=0.25=\dfrac{(3x)^3}{(0.304-x)}$

Solve for x:

You need to use a graphing calculator:

108x³ = 0.304 - x

108x³ + x - 0.304 = 0

x ≈ 0.1195 mol/liter

Then:

$C_A=0.304mol/liter-0.1195mol/liter=0.1845mol/liter\\\\C_C=3\times 0.304mol/liter=0.912mol/liter$

The equilbrium conversion is:

$\% = [0.304mol/liter-0.1845mol/liter]/(0.304mol/liter)\times 100$

$\% \approx 39\%$

3 0

3 years ago

) A toy rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward

Talja [164]

Answer:

The time interval during which the rocket engine provides upward acceleration is 2.1 s

Explanation:

The equations for the height of the rocket are as follows:

y = y0 + v0 · t + 1/2 · a · t²

and, after the engine burnout:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the rocket at time t

y0 = initial height

v0 = initial velocity

t = time

a = upward acceleration

g = acceleration due to gravity (downward)

The velocity of the rockey is given by this equation:

v = v0 + a · t (v0 = 0 because the rocket is launched from rest)

v = a · t

and after burnout:

v = v0 + g · t

Where v = velocity at time t

We know that when the altitude is 64 m the velocity is 60 m/s. Then let´s use the following equation system:

y = y0 + v0 · t + 1/2 · a · t² (y0 and v0 = 0)

v = a · t

Then:

64 m = 1/2 · a · t²

60 m/s = a · t

a = 60 m/s / t

Replacing "a = 60m/s / t" in the equation of height:

64 m = 1/2 ·( 60m/s / t) · t²

64 m = 30 m/s · t

t = 64 m / 30 m/s

t = 2.1 s

Then, the time interval during which the rocket engine provides upward acceleration is 2.1 s

5 0

3 years ago