Answer:
A) for leftmost point the coordinate is -0.28m that means it should be 0.28m towards the right.
B) for rightmost case the coordinate is 0.28m which is where komila should sit.
Explanation:
Detailed calculation and explanation is shown in the image below
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Answer:</h2>
1000th multiple of the standard reference level for intensities.
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Explanation:</h2>
The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;
β = 10 log (I / I₀) --------------------(i)
Where;
I₀ = reference intensity
Given from the question;
β = sound level = 30dB
Substitute this value into equation (i) as follows;
30 = 10 log (I / I₀)
Divide both sides by 3;
3 = log (I / I₀)
Take antilog of both sides;
10^(3) = (I / I₀)
1000 = I / I₀
Solve for I;
I = 1000I₀
Therefore the intensity of the sound is 1000 times the standard reference level for intensities (I₀)
Answer:
The distance the bungee cord that would be stretched 0.602 m, should be selected when pulled by a force of 380 N.
Explanation:
As from the given data
the length of the rope is given as l=30 m
the stretched length is given as l'=41m
the stretched length required is give as y=l'-l=41-30=11m
the mass is m=95 kg
the force is F=380 N
the gravitational acceleration is g=9.8 m/s2
The equation of k is given by equating the energy at the equilibrium point which is given as

Here
m=95 kg, g=9.8 m/s2, h=41 m, y=11 m so

Now the force is
or

So here F=380 N, k=630.92 N/m

So the distance is 0.602 m
Explanation:
8 m × (1000 mm / m) = 8000 mm