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KengaRu [80]
3 years ago
7

The rocky planets are made of material that is much (mire/less) dense than the outer planets.​

Physics
1 answer:
IRINA_888 [86]3 years ago
7 0

The outer planets (Jupiter, Saturn, Uranus, Neptune) are called the "<u>GAS</u> giants".

The rocky planets are called "rocky" because they're made of <u>ROCK</u>.

Does this help guide you to the correct choice ?

Here's another hint:  The MOST dense planet in our solar system, the one we call "Earth", is one of the 'rocky planets'.

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BRAINLEST FOR CORRECT ANSWER
xxMikexx [17]

Answer:

3kg sledgehammer swung at 1.5 m/s

Explanation:

Small Sledgehammer:

Mass:3.0

Velocity:1.5

MASS×VELOCITY=MOMENTUM

3.0×1.5= 4.5 (momentum)

Large Sledgehammer:

Mass:4.0

Velocity:0.9

4.0×0.9=3.6 (momentum)

higher momentum is the smaller Sledgehammer.

3 0
3 years ago
Qué ocurre con el espectro cuando se interpone el celofán de colores?
Travka [436]

Answer: You will only see the color that cellophane lets through

Explanation:

Let's begin by the fact the whole electromagnetic spectrum is known as "white light", which is composed by a range of colors (wavelengths).

Now, if we have a source with white light (the Sun, for example) and we interpose a cellophane of any color (let's choose red), this cellophane will act as a filter and will only let pass the color of the cellophane.

This is because the filter will absorb the other colors of the spectrum.

3 0
3 years ago
Molecules can be made of atoms of the same element only. different elements only. the same or different elements.
Ira Lisetskai [31]

Both, there are two different types of molecules to distinguish that

8 0
4 years ago
Read 2 more answers
PLEASE HELP AS FAT WILL GIVE BRAILIEST TO MOST SPECIFIC AND CORRECT ANSWER
Bas_tet [7]

Answer:

Time

Explanation:

8 0
4 years ago
An aircraft is in level flight at 225 km/hr through air at standard conditions. The lift coefficient at this speed is 0.45 and t
mojhsa [17]

Answer:

- the effective lift area for the aircraft is 8.30 m²

- the required engine thrust is 1275 N

- required power is 79.7 kW

Explanation:

Given the data in the question;

Speed V = 225 km/hr = 62.5 m/s

The lift coefficient CL = 0.45

drag coefficient CD = 0.065

mass = 900 kg

g = 9.81 m/s²

a)  the effective lift area for the aircraft

we know that for a steady level flight, weight = lift and thrust = drag

Using the equation for the lift force

F_L = C_L\frac{1}{2}ρV²A = W

we substitute

0.45 × \frac{1}{2} × 1.21 × ( 62.5 )² × A = ( 900 × 9.81 )

1081.05 × A = 8829

A = 8829 / 1081.05

A = 8.30 m²

Therefore, the effective lift area for the aircraft is 8.30 m²

b) the required engine thrust and power to maintain level flight.

we use the expression for drag force

F_D = T = C_D\frac{1}{2}ρV²A

we substitute

= 0.065 × \frac{1}{2} × 1.21 × ( 62.5 )² × 8.30

T = 1275 N

Since drag and thrust force are the same,

Therefore, the required engine thrust is 1275 N

Power required;

P = TV

p = 1275 × 62.5

p = 79687.5 W

p = ( 79687.5 / 1000 )kW

p = 79.7 kW

Therefore, required power is 79.7 kW

8 0
3 years ago
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