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Svetradugi [14.3K]
2 years ago
14

Rebecca sells greetings cards at £1.47 each. She donates 3 7 of this money to a charity. How much does the charity receive from

the sale of each card?
Mathematics
1 answer:
ANTONII [103]2 years ago
4 0
The charity receive £54.39 form the sale of each card.
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Why are inequalities important in equations
Delicious77 [7]
Because the tell if he number is big or small
4 0
3 years ago
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
ii. A machine is sold for 7,000/-. The gross loss is 20% of the cost. What are the cost and gross loss?
aleksley [76]

Given:

Selling price of a machine = 7000/-

Gross loss = 20%.

To find:

The cost and gross loss.

Solution:

Let x be the cost of machine.

According to the question,

x-20\%\text{ of }x=7000

x-\dfrac{20}{100}x=7000

x-0.2x=7000

0.8x=7000

Divide both sides by 0.8.

x=\dfrac{7000}{0.8}

x=8750

So, the cost of the machine is 8750/-.

Now,

\text{Gross Loss}=\text{Cost}-\text{Selling price}

\text{Gross Loss}=8750-7000

\text{Gross Loss}=1750

Therefore, the gross loss is 1750/-.

8 0
2 years ago
Simplify completely. (c^6/c^2)5 Enter your answer in the box.
saveliy_v [14]

the anwser is 36...................

7 0
3 years ago
3х2 x 2х3<br> Please HELP!!!!
viva [34]

Answer: 36

Step-by-step explanation: to make it easier, it is 6x6.

4 0
3 years ago
Read 2 more answers
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