Points B, D, and F are midpoints if the sides of ACE. EC=38 and DF=16. Find AC

Mathematics

1 answer:

vekshin13 years ago

7 0

Answer:

AC=32 units.

Step by step explanation:

Given information: B, D, and F are midpoints if the sides of ΔACE, EC = 38 and DF = 16.

Consider the below figure attached with this question.

According to the midpoint theorem, if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.

Since F and D are midpoints of AE and EC respectively.

Using midpoint theorem, the length of AC is twice of DF.

$AC=2\times DF$

Substitute the given values in the above equation.

$AC=2\times 16$

$AC=32$

Therefore, the length of AC is 32 units.

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Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

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Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below: