Hello,
Answer D -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12 U 12≤x<27 ⇔ -3<x<27
Answer:
x<−3+√1012 or x>−3−√1012
Step-by-step explanation:
Answer: x + 1 = 15
Step-by-step explanation:
solve -
x= 15 - 1
x = 14
x is a variable so it's not fix value in math
Probability
p=66×100/1818=3.6303630363%
After rounding to 4 decimals:
p=3.6304%