112 is the answer to your question
Answer:When you are given a problem, the two sides are equal, so they are equally weighted. As long as you do the same thing on both sides, they remain the same weight. The only way that one side can become "more weight" on a side is if you make a math mistake, and thus the answer would not satisfy the original equation
Step-by-step explanation:looked it up... have a good day!
Answer:
(x+2) (x+3) (x-5)
Step-by-step explanation:
x³-19x-30 = (x+2) (x²+ax-15) ... x³=x*(1*x²) while -30= (2)*(-15)
x³ +<u> 0</u>*x² - 19x -30 = x³ + (<u>2+a</u>)x² + (2a-15)x -30
2+a = 0
a = -2
x³-19x-30 = (x+2) (x²-2x-15) = (x+2) (x+3) (x-5)
Let's assume that the faster car has a 2 mile "head start".
The faster car is 1.2 times faster (48/40) than the slower car.
It will take five 2 mile trips to "catch" the other car.
Five 2 mile trips will take 5 * 40 seconds = 200 seconds.
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The best and most correct answer among the choices provided by the question is </span><span>C.{–10, –4.3}</span> .
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Hope my answer would be a great help for you. </span>
