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densk [106]
3 years ago
7

Why does the surfaces of the moon, mars and earth vary in appearance

Physics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

due to its distance ..............

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Which of these hazmat products are allowed in your FC?
aliina [53]

Answer: Hazmat products are allowed in your FC are:

  • A GPS unit (lithium batteries)
  • A subwoofer (magnetized materials)

Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.  

Hazardous material allowed in FC are as follows.

  • Magnetized material products like as speakers.
  • Non-spillable battery products like toy cars.
  • Lithium-ion battery containing products like laptops, mobile phones etc.
  • Non-flammable aerosol.

So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

  • A GPS unit (lithium batteries)
  • A subwoofer (magnetized materials)
7 0
2 years ago
Home Run
svp [43]

The force acting on the ball are unbalanced. Reactionary momentum force (that originated as a result of the swing of the bat) is the most powerful.

Yes friction is acting on the ball. In course of journey it would slow the ball down and make it trace a parabolic path rather than straight path as intended by hitter.

Explanation:

As the hitter hits the ball, momentum of the bat due to swing (mass of the bat*velocity provided by the batsman swinging action of bat) gets transferred on the ball on its impact with the bat.

Since ball’s mass is quite small as compared to the bat, the velocity of the ball increases by the same factor by which the ball’s mass is lower than the bat’s mass. This velocity causes forward motion of the ball (of course in the direction of bat’s motion, here the batsman intends to send the ball straight away hence the ball would move straight).

Various forces on ball is-

  • Reactionary momentum force -bat’s force (most powerful force)
  • The frictional force of the air (opposing the motion of the ball through the air)
  • Gravity force (pulling the ball down to the Earth)

As a combined effect of these force when all the force remains unbalanced, the ball moves away in the straight path under the impact of bats momentum which was most powerful of all.

Frictional force and Gravity force continue acting on the ball. While frictional forces decrease the ball velocity through the air, gravity force pulls it down thus deflecting its direction. Under the combined impact of declining bats momentum, friction force and gravity force, the ball traces a parabolic path  (in accordance with the first law of motion from Newton)

8 0
3 years ago
A bus traveling at 24 m/s slows down to 12 m/s in 5.0 seconds. What is the acceleration?
Contact [7]

Answer:

a = -2.4 m/s²

Explanation:

Given,

The initial speed of the bus, u = 24 m/s

The final speed of bus, v = 12 m/s

Time taken to reach final speed is, t = 5.0 s

The acceleration of the body is given by the change in velocity by time

                                      a = (v - u) / t

                                         = (12 - 24) / 5

                                         = -2.4 m/s²

The negative sign in the acceleration indicates that the bus is decelerating.

Therefore, the acceleration of the bus is, a = -2.4 m/s²

8 0
2 years ago
Can someone explain it with steps?
Anton [14]

Answer:

Option C is the correct answer

Explanation:

Distance travelled by car during reaction time

=15\times0.4\\\\=6m

The car stopped before hitting the animal by 1 m

Distance travelled during deceleration is 21-6-1=14m

Hence by v^2=u^2+2as

We have

0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2

Option C is the correct answer

5 0
2 years ago
Read 2 more answers
The first asteroid to be discovered is Ceres. It is the largest and most massive asteroid in our solar system’s asteroid belt, h
stira [4]

Answer:

4.81*10^{29}J

Explanation:

Since the formula for kinetic energy of an object is:

E_k = \frac{mv^2}{2}

Where m is the mass of the object and v is the speed. We can substitute m = 3*10^{21}kg and v = 17900m/s:

E_k = \frac{3*10^{21} * (17900)^2}{2} = 4.81*10^{29}J

3 0
2 years ago
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