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soldier1979 [14.2K]
2 years ago
8

What is the difference between muscular strength and muscular endurance

Physics
2 answers:
enot [183]2 years ago
6 0
Mark Brainliest please

Answer

While endurance is all about how long a muscle can perform, muscular strength is how hard it can perform.

Doing less repetitions with more weight will help you increase your strength. Doing more repetitions with lighter weights will help you build up endurance.


Muscle strength is the ability to exert a maximal amount of force for a short period of time.
Muscle endurance is the ability to do something over and over for an extended period of time without getting tired.

Summary:

1.Muscular strength is one’s ability to carry heavy weights or wield force as opposed to resistance.
2.Muscular endurance is one’s ability to perform muscular tasks for prolonged periods of time.
3.Muscular strength is linked to fast-twitch muscle fibers while endurance is linked to slow-twitch muscle fibers.
4.Muscular strength must be the focus of strength-based sports like rugby while endurance is the priority of long-lasting sports like running.
MAXImum [283]2 years ago
4 0
Muscular strength is a measure of how much force you can exert in one repetition. Muscular endurance refers to the ability to perform a specific muscular action for a prolonged period of time.
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Blood in a carotid artery carrying blood to the head is moving at 0.15 m/s when it reaches a section where plaque has narrowed t
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Answer:

26.9 Pa

Explanation:

We can answer this question by using the continuity equation, which states that the volume flow rate of a fluid in a pipe must be constant; mathematically:

A_1 v_1 = A_2 v_2 (1)

where

A_1 is the cross-sectional area of the 1st section of the pipe

A_2 is the cross-sectional area of the 2nd section of the pipe

v_1 is the velocity of the 1st section of the pipe

v_2 is the velocity of the 2nd section of the pipe

In this problem we have:

v_1=0.15 m/s is the velocity of blood in the 1st section

The diameter of the 2nd section is 74% of that of the 1st section, so

d_2=0.74d_1

The cross-sectional area is proportional to the square of the diameter, so:

A_2=(0.74)^2 A_1=0.548 A_1

And solving eq.(1) for v2, we find the final velocity:

v_2=\frac{A_1 v_1}{A_2}=\frac{A_1 (0.15)}{0.548 A_1}=0.274 m/s

Now we can use Bernoulli's equation to find the pressure drop:

p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho v_2^2

where

\rho=1025 kg/m^3 is the blood density

p_1,p_2 are the initial and final pressure

So the pressure drop is:

p_1 - p_2 = \frac{1}{2}\rho (v_2^2-v_1^2)=\frac{1}{2}(1025)(0.274^2-0.15^2)=26.9 Pa

8 0
3 years ago
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