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2 years ago

What is the equilibrium constant for the following reaction at 25 °c?

Physics

1 answer:

sdas [7]2 years ago

4 0

The equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

<h3>What is equilibrium constant?</h3>

The equilibrium constant in a chemical reaction is the reaction quotient when the chemical reaction is at equilibrium constant.

The equilibrium constant for the for reaction at 25 °c given in the problem as,

$2A\rightleftharpoons B+C, K_1=1.0 \\2B\rightleftharpoons C+D, K_2=16 \\2C+D\rightleftharpoons 2P, K_3=25 \\$

Now, the reaction for which the equilibrium constant at 25 °c has to be find out is,

$P\rightleftharpoons A+\dfrac{1}{2}B$

$K_4=\sqrt{\dfrac{1}{K_1}+\dfrac{1}{K_2}+\dfrac{1}{K_3}}\\K_4=\sqrt{\dfrac{1}{25}+\dfrac{1}{16}+\dfrac{1}{1}}\\K_4=\dfrac{1}{20}$

Thus, the equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

Learn more about the equilibrium constant here;

brainly.com/question/12858312

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