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1 year ago

What is the equilibrium constant for the following reaction at 25 °c?

Physics

1 answer:

sdas [7]1 year ago

4 0

The equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

<h3>What is equilibrium constant?</h3>

The equilibrium constant in a chemical reaction is the reaction quotient when the chemical reaction is at equilibrium constant.

The equilibrium constant for the for reaction at 25 °c given in the problem as,

$2A\rightleftharpoons B+C, K_1=1.0 \\2B\rightleftharpoons C+D, K_2=16 \\2C+D\rightleftharpoons 2P, K_3=25 \\$

Now, the reaction for which the equilibrium constant at 25 °c has to be find out is,

$P\rightleftharpoons A+\dfrac{1}{2}B$

$K_4=\sqrt{\dfrac{1}{K_1}+\dfrac{1}{K_2}+\dfrac{1}{K_3}}\\K_4=\sqrt{\dfrac{1}{25}+\dfrac{1}{16}+\dfrac{1}{1}}\\K_4=\dfrac{1}{20}$

Thus, the equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

Learn more about the equilibrium constant here;

brainly.com/question/12858312

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1 year ago

What is the melting point of substance A?

Misha Larkins [42]

Answer:

Solids are easily recognized by their ability to retain a fixed shape and definite volume. Particles making

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To change the temperature of a solid, heat energy must be added. The amount of heat energy that changes

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The general equation for calculating heat energy to change the temperature of a solid is:

Heat = Mass x Specific Heat (solid) x Temperature Change

Q = m c DT

10 g 10 g 10 g 10 g 10 g 10 g

Calculate the heat necessary to change 10 g of ice(s) at -20 °C to 10 g of ice(s) at 0°C. (A-B)

Q = mc∆T = (10 g) (2.1 J/g°C) (20°C) = 420 J

If you continue to add heat energy once the temperature of the ice reaches 0°C , the heat absorbed is called

the heat of fusion (Lf). This heat is used to cause a change of phase (from a solid to a liquid). This heat is

increasing the potential energy of the molecules of the solid. No temperature change takes place. Each

substance has its own heat of fusion. The heat of fusion for ice is 340 Joules/g. Exactly the same amount

of heat is given up when 1.0 g of water is changed to ice. This heat is called the heat of crystallization.

The general equation for calculating heat energy to change a solid to a liquid is:

Heat = Mass x Heat of Fusion

Q = m Lf

Calculate the heat necessary to change 10 g of ice(s) at 0°C to 10 g of water(l) at 0°C.(B-C)

Explanation:

Q = mLf = (10 g)( 340 J/g) = 3400 J

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3 years ago

What kind of surface is suitable for infared radiation

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Answer:

Different surfaces

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3 years ago

The water in the plumbing in a house is at a gauge pressure of 300,000 pa. What force does this cause on the top of the tank ins

liraira [26]

Answer:

60 000 N

Explanation:

1 pa = 1 N/m^2

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but only an area of .2 m^2

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