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worty [1.4K]
2 years ago
5

What is the equilibrium constant for the following reaction at 25 °c?

Physics
1 answer:
sdas [7]2 years ago
4 0

The equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

<h3>What is equilibrium constant?</h3>

The equilibrium constant in a chemical reaction is the reaction quotient when the chemical reaction is at equilibrium constant.

The equilibrium constant for the for reaction at 25 °c given in the problem as,

2A\rightleftharpoons B+C, K_1=1.0 \\2B\rightleftharpoons C+D, K_2=16 \\2C+D\rightleftharpoons 2P, K_3=25 \\

Now, the reaction for which the equilibrium constant at 25 °c has to be find out is,

P\rightleftharpoons A+\dfrac{1}{2}B

K_4=\sqrt{\dfrac{1}{K_1}+\dfrac{1}{K_2}+\dfrac{1}{K_3}}\\K_4=\sqrt{\dfrac{1}{25}+\dfrac{1}{16}+\dfrac{1}{1}}\\K_4=\dfrac{1}{20}

Thus, the equilibrium constant for the provided reaction at the temperature of 25 degree Celsius is 1/20.

Learn more about the equilibrium constant here;

brainly.com/question/12858312

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A 2 kg box of taffy candy has 40j of potential energy relative to the ground. Its height above the ground is​
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2.04m

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Answer:

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D = m/v .............................. Equation 1.

Where D = Density of the solid copper sphere, m = mass of the solid copper sphere, v = volume of the solid copper sphere.

Making v the subject of the equation,

v = m/D............................... Equation 2

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Substituting into equation 2

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Since the copper sphere is to be drawn into wire,

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Where d = diameter of the wire, L = length of the wire.

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v = πd²L/4 ........................ equation 3.

making L the subject of the equation,

L = 4v/πd²..................... Equation 4

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Substitute into equation 4

L = 4×0.0085379/(3.15×0.0095²)

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