The answer is <span>A. The two animal species are very closely related.
If the two animal species are very closely related, that means their genome information is very similar and that information for embryonic development is also very similar, but it will not be identical. Stages of embryonic development from the beginning to the end are same only in the same species. In different species, they will differ in lesser or greater extent which depend on how closely this different species are related.</span>
The formation of the cell plate (or phragmoplast) is similar to the formation of a cleavage furrow in animal cells, which separates two cells during mitosis and meiosis. Therefore, this occurs during cytokinesis
<span>The answer is d. Meiosis produces haploid cells, while mitosis produces diploid cells.
Meiosis begins with diploid cells but further divides into four daughter cells. Mitosis produces 2 diploid cells</span>
um, no. False. Cheetah's came from desert cats not sabre tooth tigers
The givens are as follows:
initial velocity (vi) = 6 m/sec
acceleration = -9.8 m/sec^2 (the negative sign refers to the direction)
final velocity (v) = 1.1 m/sec
initial position (xi) = 0 meters
Now, we will use the equations of motion to get the displacement as follows:
v = vi + at
1.1 = 6 - 9.8t
9.8t = 6-1.1 = 4.9
t = 0.5 sec
x = xi + vit + 0.5at^t
x = 0 + (6)(0.5) + 0.5(-9.8)(0.5)^2
x = 1.775 meters