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UNO [17]
4 years ago
14

There are 12 students in a classroom, including the triplets joey, chloe, and zoe. If 3 of the 12 are randomly selcted to give s

peeches, what is the probability that joey with be first, chloe will be second, and zoe will be third?
A: 1/1320 B: 1/4 C: 1/48 D: 1/220
Mathematics
1 answer:
forsale [732]4 years ago
3 0

The probability of choosing Joey first is  1/12 .

If that happens, the probability of choosing Chloe next is  1/11 .

Then, the probability of choosing Zoe after that is  1/10 .

The probability of all these things happening is

          (1/12) x (1/11) x (1/10) 

       =  1/1320 = 0.00076 = 0.076 percent 

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Studentka2010 [4]

Answer:

D 9/26

Step-by-step explanation:

Out of the 10th graders there are 104 total responses.  Knowing we only need data from 10th graders we can ignore everything else.  36/104 10th graders like cats and if you divide that by 4 you'll get the only possible answer of 9/26.  D 9/26 10th graders like cats.

6 0
3 years ago
Read 2 more answers
A moving company charges $0.70 per pound for a move from New York to Florida. A family estimates that their belongings weigh abo
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First, how many pounds are equal to 1 ton?  2000

Then, $0.70 x 2000 pounds

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Yep. It's that simple. :)

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3 years ago
A piece of cardboard is 15 inches by 30 inches. A square is to be cut from each corner and the sides folded up to make an open-t
solmaris [256]

Answer:

Maximum volume = 649.519 cubic inches

Step-by-step explanation:

A rectangular piece of cardboard of side 15 inches by 30 inches is cut in such that a square is cut from each corner. Let x be the side of this square cut. When it was folded to make the box the height of box becomes x, length becomes (30-2x) and the width becomes (15-2x).

Volume is given by  

V = V = Length\times Width\times Height\\V = (30 - 2x)(15-2x)x= 4x^3-90x^2+450x\\So,\\V(x) = 4x^3-90x^2+450x

First, we differentiate V(x) with respect to x, to get,

\frac{d(V(x))}{dx} = \frac{d(4x^3-12x^2+9x)}{dx} = 12x^2 - 180x +450

Equating the first derivative to zero, we get,

\frac{d(V(x))}{dx} = 0\\\\12x^2 - 180x +450 = 0

Solving, with the help of quadratic formula, we get,

x = \displaystyle\frac{5(3+\sqrt{3})}{2}, \frac{5(3-\sqrt{3})}{2},

Again differentiation V(x), with respect to x, we get,

\frac{d^2(V(x))}{dx^2} = 24x - 180

At x =

\displaystyle\frac{5(3-\sqrt{3})}{2},

\frac{d^2(V(x))}{dx^2} < 0

Thus, by double derivative test, the maxima occurs at

x = \displaystyle\frac{5(3-\sqrt{3})}{2} for V(x).

Thus, largest volume the box can have occurs when x = \displaystyle\frac{5(3-\sqrt{3})}{2}}.

Maximum volume =

V(\displaystyle\frac{5(3-\sqrt{3})}{2}) = (30 - 2x)(15-2x)x = 649.5191\text{ cubic inches}

8 0
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Step-by-step explanation:

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ANEK [815]
The answer is \frac{x+1.2}{5} =3.6
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