Yeah yeah I know it math

(p2+3p+6)+(2p2+6p+6) Please get this right. AND DON'T SPAM!

gayaneshka [121]

(p² + 3p + 6) + (2p² + 6p + 6)

First you must combine (aka sum) like terms. Like terms are numbers that have matching variables OR are numbers with out variables OR have matching variables with matching exponents. In this case the like terms are p² and 2p² (they both have the exponent p that is squared); 3p and 6p (they both have the variable p attached); and 6 and 6 (both numbers without variables)

(p² + 2p²) + (3p + 6p) + (6 + 6)

3p² + 9p + 12

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

3 years ago

Melanie found 50 seashells on the beach, she gave Sam some of

monitta

She gave him 28 seashells

6 0

2 years ago

a car covers a distance of 450 miles in one minute where is a train covers 69 km in 45 minutes find the ratio of their speed

liberstina [14]

Answer:

69 plus 45 mius 450 equals 98

7 0

3 years ago

An airplane climbs 100 feet during the first second after takeoff. In each succeeding second it climbs 100 feet more than it cli

tigry1 [53]

Answer:

15 seconds.

Step-by-step explanation:

∵ The distance covered by plane in first second = 100 ft,

Also, in each succeeding second it climbs 100 feet more than it climbed during the previous second,

So, distance covered in second second = 200,

In third second = 300,

In fourth second = 400,

............, so on....

Thus, the total distance covered by plane in n seconds = 100 + 200 + 300 +400......... upto n seconds

$=\frac{n}{2}(2\times 100 + (n-1)100)$ ( Sum of AP )

$=\frac{n}{2}(200+100n-100)$

$=\frac{n}{2}(100+100n)$

$=50n+50n^2$

Suppose the distance covered in n seconds is 12,000 feet,

$\implies 50n+50n^2=12000$

$n+n^2=240$

$n^2+n-240=0$

$n^2+16n-15n-240=0$

$n(n+16)-15(n+16)=0$

$(n-15)(n+16)=0$

$\implies n=15\text{ or }n=-16$

∵ n can not be negative,

Hence, after 15 seconds the plane will reach an altitude of 12,000 feet above its takeoff height.

6 0

3 years ago

Read 2 more answers

Which expression can be used to find the price of a $400 telescope after a 32% markup? Select all that apply.

emmainna [20.7K]

Answer:

Expressions C and D correctly determine the markup price.

Step-by-step explanation:

A markup in mathematics is when an object's price is raised by a certain percentage. Therefore, because we are told that the telescope is originally $400 and is marked up by 32%, we can actually mathematically evaluate this.

When you markup a price, you multiply the original price by $1+x$ , where x is the percentage at which the object is marked up. However, x needs to be in decimal form for it to work out.

$\frac{32}{100} = \small\boxed{0.32}$

Therefore, with this new decimal, we can add 1 to it.

$1 + 0.32=\small\boxed{1.32}$

Finally, we multiply this result by the original price.

$1.32 \times 400=\small\boxed{528}$

Therefore, we can already confirm that Expression C is one way to find the markup price.

We can eliminate expression A because it did not use the formula $1+x$ . It only uses the decimal form of the percentage.
We can eliminate expression B because the division to convert from the percentage form to the decimal form is flawed (the expression divided by 10 instead of 100) and also forgot to add 1 to the determined value.

Now, we can test the math for expressions D and E to see if either of these will equal $528.

Expression D is basically saying to add 32% of 400 to the original price. This would work out because we marked up the original price by 32%. Therefore, we can confirm that Expression D is also an expression that can be used to determine the markup price.

$400 + 400(0.32)\\400(0.32) = 128\\400 + 128 = \small\boxed{528}$

Finally, we also need to check expression E. This expression is saying to add the already marked up price to 400. This would not be correct.

$400 \times 400(1.32)\\400(1.32) = 528\\400 \times 528 = \small\boxed{\$ 211,200}$

Therefore, it has been determined that Expression C & Expression D are both equations that will find a markup price.

7 0

3 years ago