Answer:
x
^2
−
2
y
^2
−8
x
y
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
We have the sum of first n terms of an AP,
Sn = n/2 [2a+(n−1)d]
Given,
36= 6/2 [2a+(6−1)d]
12=2a+5d ---------(1)
256= 16/2 [2a+(16−1)d]
32=2a+15d ---------(2)
Subtracting, (1) from (2)
32−12=2a+15d−(2a+5d)
20=10d ⟹d=2
Substituting for d in (1),
12=2a+5(2)=2(a+5)
6=a+5 ⟹a=1
∴ The sum of first 10 terms of an AP,
S10 = 10/2 [2(1)+(10−1)2]
S10 =5[2+18]
S10 =100
This is the sum of the first 10 terms.
Hope it will help.
Answer:
1.) n-10
2.) 4 / x=x (dont trust me on this)
3.) -8n+1
4.) 1/2 - 19 ( dont trust me on this)
5.)3/5-21 or 3/5>21
6.)x^+15
Step-by-step explanation:
I tried double check it
its been awhile
Answer:
a,d, even win a new one and it do you like
Step-by-step explanation:
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